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lys-0071 [83]
4 years ago
12

Does 23y+50+27y=50y+50 have one solution, no solution, or infinite solutions

Mathematics
2 answers:
stellarik [79]4 years ago
7 0
The answer is infinite solutions.

subtract 50 from each side to get 
23y+27y=50y

ad 23y and 27y to get 50y
50y=50y
and no matter what number you put in place you get the correct answer
dimaraw [331]4 years ago
5 0

Answer:

Infinite solutions

Step-by-step explanation:

To find the number of solutions the equation above has, we will follow the steps below:

23y+50+27y=50y+50

First, we will collect like term, that is, we will move all those values with y variables to the left-side and then move all the constants to the right-hand side. Thus;

23y + 27 y - 50y = 50 -50

50y - 50y = 0

50y = 50 y

Therefore, this equation has an infinite solution

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Four less than the product of 6 and a number n is -30.<br> What is the number? _____
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7 0
3 years ago
What is the answer in the picture above
Rudiy27

To solve this you must isolate x. First add 1 to both sides

x² - 1 + 1 = 0 + 1

x² = 1

Now you must take the square root of both sides to cancel out the square from the x

√x² = √1

x = 1 and x = -1

When you take the square root of a number you must remember to take both the positive and negative of the number

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3 0
3 years ago
Can someone help me please ? Thanks!
White raven [17]
Answer: Choice A) x = 15; y = 17

---------------------

Explanation:

The "7x+7" angle and the "112 degree" angle are congruent. They are vertical angles. So
7x+7 = 112
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We technically have enough to stop here, but let's keep going to find y

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4 years ago
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