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son4ous [18]
3 years ago
6

Create an arithmetic sequence with a common difference of -10

Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

0, -10, -20, -30, -40, -50, ..., -10(n-1)

Step-by-step explanation:

An arithmetic sequence with a common difference of -10 just indicates that each term adds negative ten to the prior one, which is just subtracting ten.  If you slap a random value as the beginning, zero in my example, then you spam subtract negative tens, you get an arithmetic sequence.  The variable "n" is just the term number - 0 was n=1, -10 was n=2, -20 was n=3, etc.

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What is a fraction of a fraction
Vikentia [17]
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ When it comes to dividing fractions, there is a rule you must now.

It's called Keep Flip Change.

I'll give you an example:

\frac{2}{7} / \frac{4}{6}

Keep the first fraction exactly as it is

Flip the second fraction upside down (switch the numerator and denominator around)

Change the sign to a multiplication.

This is how it should look:

\frac{2}{7} *\frac{6}{4}

Now you just multiply them as you normally would to get an answer of:

\frac{12}{28}

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

6 0
3 years ago
Find the sum and then classify it.5/6+√91
IgorLugansk [536]
HEY THERE

FIRT ADDISON OF 5/6+√9

5/6+9.5393 = 10.3727253.

NOW CLASSIFICATION:- 10.40

HOPE IT HELPS YOU.
6 0
3 years ago
Read 2 more answers
Which of the following are equivalent ratios?<br>A: 12 : 16<br>B: 3 : 5<br>C: 2 : 3<br>D: 6 : 8​
Alla [95]

The equivalent ratios are A and D.

Here's an explanation:

When you look at D, you see that 12 is a multiple of 6, and 16 is a multiple of 8. So you know that it looks like they're equivalent. Then you test it out, 12/2=6. 16/2=8. so 12:16 = 6:8. Eyeballing it first can save time sometimes.

8 0
4 years ago
A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the semin
Elena L [17]

Answer:

16 people

Step-by-step explanation:

This is a set problem

let first session be a

let second session be b

128 people attended at least one session = a∪b

a. 3/4 attended both session 1&2 = a∩b

b. 7/8 attended session 2 = p(b) i.e population b

c x attended session 1 = p(a) i.e. population a

lets get the figures.

  • For both sessions 3/4 × 128 = 96 = a∩b
  • For second session 7/8 × 128 = 112 = b
  • The formular is a∪b = p(a) + p(b) - a∩b
  • a∪b = 128 (they at least one session)

lets substitute into the equation

let p(a) be x

128 = x + 112 - 96

128 = x + 16

x = 112 - no of people that attended the morning session.

But to find those that ONLY attended morning session

x - a∩b

112 - 96 = 16

3 0
3 years ago
Read 2 more answers
Evaluate the expression 2^5/2^3 and write your<br> answer as a fraction in simplest form.
Semenov [28]

Answer:

32/8 simplest is 4/1 or 4

Step-by-step explanation:

7 0
3 years ago
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