Area of the triangle = (1/2)*base*height
For right triangle base and height can be legs.
We have one leg = 5 ft. (Lets think it is a base.)
We need to find the other leg.
We are going to use Pythagorean theorem.
5² + b²=13²
b²=144
b=12 (It is going to be our height.)
Area of the triangle = (1/2)*5*12= 30 ft²
Area of the triangle = 30 ft²
Let p = weight of papaya and g = weight of grapes.
Then (3/4)g = (3/5)p. Since the weight of grapes is x + 28,
(3/4)(x + 28) = (3/5)p. We must solve for x. To do this, mult. both sides by (5/3):
(5/3)(3/4)(x+28) = (5/3)(3/5)p
Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).
Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.
The answer to the question