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enyata [817]
3 years ago
15

Four friends are standing in line to buy tickets. Carlos is not first in line.Paige is ahead of of Kate.Lisa is last in line.Who

's first in line
Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0
Paige is first in line.

Lisa is last in line, so Lisa is not first in line. Carlos is not first in line, as the problem says. Paige is ahead of Kate, which means Kate is not first in line.

Hope this helps~


iren2701 [21]3 years ago
4 0
Paige is ahead of kate. It dosen't say she is behind anyone or last in the line. Carlos is not first in line. Kate cannot be first because someone is ahead of her. And lisa is last. So the answer is definitely paige. Hope i helped. Have a nice day. 
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

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(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

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(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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