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Vera_Pavlovna [14]
3 years ago
14

What equivalent fractions can you use to find the difference of 5 3/12 - 1 4/9

Mathematics
1 answer:
Leokris [45]3 years ago
8 0
5 3/12 = 63/12
1 4/9 = 13/9
common denominator is 36
63/12 x 3/3 = 189/36
13/9 x 4/4 = 52/36
189/36 - 52/36 = 137/36
137/36 = 3 29/36
HOPE THIS HELPS BOIIIIIIIII
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Alecsey [184]

Answer: you multiply the 2 numbers and divide it by half then your answer is the easy way to do it.

Step-by-step explanation:

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13. Simplify –3√ 2 + 3√ 8 A. 0 B. 3√ 2 C. 9√ 2 D. –3√ 2
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Answer:

B. 3√2.

Step-by-step explanation:

  1. -3√2 + 3√4x2
  2. -3√2 + 6√2
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These are all of the steps to completely, find the correct answer to your question.

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Find the 12th term of the arithmetic sequence 2a - b, 3a - 2b, 4a - 3b​
Alina [70]

Answer:

the 12th term of the arithmetic sequence would be 13a - 12b

Step-by-step explanation:

as you can see from the sequence, it goes up by 1. 2a - b became 3a -2b as an example.

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Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2
tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

<u>1. 2x^2 - 7x + 3</u>

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

  • a = 2
  • b = -7
  • c = 3

we can use the quadratic formula: x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}

Substitute the a, b, and c values into the quadratic formula: x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}

Now simplify using the laws of pemdas: x=\frac{7\pm\sqrt{(49)-(24)} }{4}

Simplify even further: x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}

Now split this equation into two equations to solve for x: x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

\boxed {x=3,\frac{1}{2} }

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

  • x - 3 = 0
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After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

<u>2. 3x^2 + 7x + 2</u>

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

  • 3x + 1 = 0
  • x + 2 = 0

Solve.

<u>First factor:</u> 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

<u>Second factor:</u> x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

\boxed {x = -\frac{1}{3} , -2}

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