Given profit,
p(t)=0.4t^2+5.3t-8
After the first year, t=1
p(1)=0.4*(1^2)+5.3*1-8=-2.3
Answer: the annual loss of the coffee shop after the first year (i.e. the second year) is $2,300.
Answer:
$6500
Step-by-step explanation:
Let the amount of money invested by Lian be $x
Interest rate = 5.2% per year
interest earned in first year will be 5.2% of amount of money invested by Lian .
(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )
interest earned in one year if money invested by Lian is $x
= 5.2% of $x (1)
But , it is given in one year she received interest of 338 dollars
so, 338 dollars must be equal to 5.2% of $x
equating $338 with 5.2% of $x , we have
5.2% of x = 338
=> (5.2/100) * x = 338
=>5.2 x = 338*100
=> x = 33800/5.2 = 6500.
Thus, amount of money Lian invested is $6500.
Answer:
The weight of container C is 2.1kg.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
x is the weight of container A.
y is the weight of container B.
z is the weight of container C.
The average weight of 3 containers A,B and C is 3.2kg.
This means that the total weight is 3*3.2 = 9.6kg. So
Container A is twice as heavy as container B.
This means that 
.
Containers B is 400 g heavier than container C.
400g is 0.4kg. So
This means that 
, or 
Replacing y and z as functions of x in the first equation:
Container C
The weight of container C is 2.1kg.
