Answer:
y=4,x=1
Step-by-step explanation:
4x+y=8
x+y=5
subtract equation 2 from equation 1
3x + 0=3
3x=3
divide both sides by 3
x=1
substitute for x=1 in equation 2
x+y=5
1+y=5
y=5-1(collecting like terms)
y=4
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Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6
Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.
Probability of selecting a basketball card = 6/10 = 0.6
Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated.
Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
2)
P(4,-4) -->(-4, 7)
4 - 8 = -4 -------->left 8
-4 + 11 = 7 -------->up 11
Answer: left 8; up 11
3)
C(3,-1) , left 4 up 1
3 - 4 = -1 -------->left 4
-1 + 1 = 0 -------->up 1
a)
(x , y) -->(x - 4 , y +1)
C(3, -1) -->C'(-1 , 0)
b)
(x , y) --> (x - 4, y + 1); (-1 , 0)
