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marishachu [46]
3 years ago
7

Check whether (0, -2) is solution of the equation x - 2y = 4 or not

Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Plugin x = 0 & y = -2 in the LHS of the equation. After substituting, if you get the RHS, then this point is the solution of the equation.

x - 2y = 0 - 2*(-2)

         = 0 + 4

         = 4  = RHS.

(0,-2) is solution of the equation.

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If f(x) = 5x2 − 2x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints. R6 =
Leona [35]

Answer:

46.375

Step-by-step explanation:

Given information:

f(x)=5x^2-2x

where, 0 ≤ x ≤ 3.

We need to divde the interval [0,3] in 6 equal parts.

The length of each sub interval is

\dfrac{b-a}{n}=\dfrac{3-0}{6}=0.5

Right end points are 0.5, 1, 1.5, 2, 2.5, 3.

The value function on each right end point are

f(0.5)=5(0.5)^2-2(0.5)=0.25

f(1)=5(1)^2-2(1)=3

f(1.5)=5(1.5)^2-2(1.5)=8.25

f(2)=5(2)^2-2(2)=16

f(2.5)=5(2.5)^2-2(2.5)=26.25

f(3)=5(3)^2-2(3)=39

Riemann sum:

\sum_{n=1}^6 f(x_n)\Delta x_n

Sum=[f(0.5)+f(1)+f(1.5)+f(2)+f(2.5)+f(3)]\times 0.5

Sum=[0.25+3+8.25+16+26.25+39]\times 0.5

Sum=92.75\times 0.5

Sum=46.375

Therefore, the Riemann sum with n = 6 is 46.375.

6 0
3 years ago
WILL GIVE BRAINLIEST!! 2) Match the graph with its function. Which is an example of growth/decay?
Neporo4naja [7]

The exponential growth is: f(x) = 15*(1.25)^x

And its graph is the first one.

The exponential decay is: f(x) = 250*(0.87)^x

And its graph is the second one.

<h3>How to identify the exponential equations?</h3>

The general exponential equation is of the form:

y = A*(b)^x

Where A is the initial value and b is the base.

  • If b > 1, then we have an exponential growth.
  • if 1 > b > 0, then we have an exponential decay.

Here the two functions are:

f(x) = 250*(0.87)^x

f(x) = 15*(1.25)^x

As you can see, the base for the first one is smaller than 1, then it is an exponential decay (and it has a decreasing graph, so the graph of this one is the second graph).

For the second function, we have the base b = 1.25, which is larger than 1, so it is an exponential growth, and its graph is an increasing graph, which is the first one.

If you want to learn more about exponential functions:

brainly.com/question/11464095

#SPJ1

6 0
2 years ago
Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.
koban [17]

Given:

Consider the completer question is "Find the derivative \dfrac{dy}{dx} for y=\dfrac{x^2-4x}{x^3-5}."

To find:

The derivative \dfrac{dy}{dx}.

Solution:

Chain rule: \dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)

Quotient rule: \dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}

We have,

y=\dfrac{x^2-4x}{x^3-5}

Differentiate with respect to x.

\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)

Using chain rule and quotient rule, we get

\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}

Therefore, the required answer is \dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}.

4 0
3 years ago
Can someone help me please I don’t understand
Alchen [17]

Answer:

answer is 3.144

Step-by-step explanation:

6 0
3 years ago
Solve the equation s/r -2=t/r <br>solve for r​
vivado [14]

Answer: have a good day :)

r=\frac{s}{2}-\frac{t}{2}

8 0
3 years ago
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