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Alex17521 [72]
3 years ago
11

Marbleslides: Lines

Mathematics
1 answer:
Arada [10]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
krek1111 [17]

Answer:

34%

Step-by-step explanation:

According to the empirical rule, 68% of all of the data in a normal distribution falls within one standard deviation of the mean.

Applying to this particular case, 68% of the requests fall within (50 - 7) and (50+ 7). The percentage of requests from 43 to 50 is equal to the percentage of requests from 50 to 57.

Therefore, the percentage of light bulb replacement requests numbering between 50 and 57 is 68/2 =  34%.

8 0
4 years ago
What’s the answer???
gladu [14]

Answer:

17

Step-by-step explanation:

6 0
3 years ago
QRST is a square. PQ = 2√ RU = 4<br> What is the length of SU? Round to the nearest tenth.
777dan777 [17]

Answer:

SU=3.5\ units

Step-by-step explanation:

step 1

In the isosceles right triangle PQT

PQ=PT ----> because is an isosceles triangle

Applying the Pythagoras Theorem

we have

PQ=PT =\sqrt{2}\ units

QT^{2}=PQ^{2} +PT^{2}

substitute the values

QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}

QT^{2}=4

QT=2\ units

step 2

In the square QRST

RS=QT=2\ units

step 3

In the right triangle RSU

Applying the Pythagoras Theorem

RU^{2}=RS^{2} +SU^{2}

we have

RU=4\ units

RS=2\ units

substitute the values and solve for SU

4^{2}=2^{2} +SU^{2}

SU^{2}=4^{2}-2^{2}

SU^{2}=12

SU=2\sqrt{3}\ units

SU=3.5\ units

8 0
3 years ago
Which of the following triangles are impossible to draw? Choose all that apply.
Luda [366]
<span>These triangles are impossible:

a triangle with sides of 3 inches, 4 inches, and 8 inches
(the longest side is greater than the sum of the other 2 sides)

an obtuse equilateral triangle
(all angles in an </span><span>equilateral triangle are acute)

</span>
<span>a triangle with two right angles
The angles of ALL triangles must sum exactly to 180 degrees.  Two right angles sum to 180 degrees so the third angle would have to be zero degrees.



</span>
8 0
3 years ago
Read 2 more answers
How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!
Hitman42 [59]
The i in the denominator is missing in the second expression. It should be

\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}

This follows from

e^{iat}=\cos at+i\sin at
e^{-iat}=\cos at-i\sin at
\implies e^{iat}-e^{-iat}=2i\sin at
\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}
8 0
4 years ago
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