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Completa la tabla sobre o debajo segun corresponda

rusak2 [61]

complete the table above or below as appropriate of segun corresponda.

Spanish 22% English 25% Periodism 18% Physical Education 17% Biology 18%

1. Thirty-five percent of students studied science; hence, 35 (35 = thirty-and-five) = thirty-and-five.

2. One-hundred and thirty-three percent of students studied English or periodical studies — 25+18 = 43 (forty-three = one hundred and thirty-three).

3. One-sixty-five percent of students did not study science — 22+25+18 = 65 (sixty-five = one-sixty-five)

4. Eighty two percent of students did not study biology — 17 + 22 + 25 + 18 = 82 (eighty two Equals eighteen and two).

5. One-quarter and seven percent of students studied either English or Spanish — 25+22 = 47 (quarter and seven = 47).

6. One hundred and three percent of students — 17+18+18 = 53 (one hundred and thirty equals five) — did not study languages.

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1 year ago

Nathaniel and meteorologists keep track of the amount of rain each year relative to the amount of rain in 2000 two years of data

dlinn [17]

Answer:

None is shown luv.

Step-by-step explanation:

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2 years ago

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The angle of elevation from a soccer ball on the ground to the ground to the top of the goal 34 degrees. If the goal is 8 ft tal

GarryVolchara [31]

Check the picture below.

make sure your calculator is in Degree mode.

6 0

3 years ago

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B13%5E%7B2%7D%20%7D%20-12%5E%7B2%7D" id="TexFormula1" title="\sqrt{13^{2} } -12^{2}"

ankoles [38]

Simplify the radical, then combine the numbers.
-131

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2 years ago