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Kryger [21]
3 years ago
10

Area of the park is halfway between 2.4 and 2.5 what is the area of the park

Mathematics
1 answer:
victus00 [196]3 years ago
7 0
First, list the fractions in between. 2.41, 2.42, 2.43, 2.44, 2.45, 2.46, 2.47, 2.48, 2.49, then 2.5. When looking at the list, you can see that 2.45 is halfway between 2.4 and 2.5. One other way to find it is thinking what is between 0 to 10? The answer is 5. Therefore, halfway between 2.4 and 2.5 is 2.45, and that is the area of the park.
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Write an equation of the line that is parallel to 5x+20y=10 and passes through the point (8,3).
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Answer:

20y = -5x + 10

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y - 3 = -1/4(x - 8)

y - 3 = -1/4x + 2

y = -1/4x + 5

Step-by-step explanation:

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Use the product property of roots to choose the expression equivalent to 3√5x*3√25x^2?
nignag [31]

Answer: \sqrt[3]{125x^3}.


Step-by-step explanation: Given radical expression

\sqrt[3]{5x} \times \sqrt[3]{25x^2}.

According to the product property of roots.

\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}

On applying above rule, we get

\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}

5 × 25 = 125 and

x \times x^2 = x^3

Therefore,

\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}

<h3>So, the correct option would be second option \sqrt[3]{125x^3}.</h3>

3 0
3 years ago
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Irina18 [472]

Explanation:

Pair 1 is true if Jeff's monthly income is $600/20% = $3,000.

Pair 2 is true if Jeff's monthly income is $1200/10% = $12,000.

Both pairs can be true if Jeff's monthly income increased by a factor of 4 in the 20 years from 1990 to 2010.

Obviously, Jeff spent more on housing in 2010. (Fortunately for Jeff, that larger expenditure was a smaller fraction of his income.)

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