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3 years ago

A number that has a digit in tenths place, hundredths place or beyond

Mathematics

2 answers:

givi [52]3 years ago

8 0

Decimal- A number that has a digit in the tenths place, hundredths place, and/ or beyond.

castortr0y [4]3 years ago

6 0

The answer is decimal hope this helps

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On Thursday, 72% of the customers at a frozen yogurt shop ordered vanilla frozen yogurt. If 180 customers ordered vanilla frozen

Ber [7]

180 of 72% is 129.6. 180*72= 12960. Since 72% = .72, you need to put the decimal 2 places behind the decimal.

6 0

3 years ago

Read 2 more answers

Solve the system of elimination -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5

Dahasolnce [82]

Answer:

x = 1 , y = 1 and z = 0

Step-by-step explanation:

-2x+2y+3z=0 ------(1)

-2x-y+z=-3 --------(2)

2x+3y+3z=5 ---------(3)

<u>To find the values of x,y and z</u>

(3) - (2)⇒ 2y + 4z = 2

y + 2z = 1 --------(4)

(1) - (2)⇒ 3y +2z =3 ---(5)

(5) - (4)⇒ 2y = 2

y = 1

Substituting the value of y in (4) we get z =0

Substituting the value of y and z in (1) we get x = 1

Therefore x = 1 , y = 1 and z = 0

5 0

3 years ago

Find the value of b.

Naya [18.7K]

Step-by-step explanation:

The value of b will be 43° as it is vertically opposite angle.. !!

6 0

1 year ago

Read 2 more answers

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

2 years ago

Find the value of x.

marusya05 [52]

The two angles are vertically opposite when their vertexs share a common point on a set of two lines that cross.

2x + 8 = 70 Subtract 8 from both sides

2x + 8 - 8 = 70 - 8 Combine

2x = 62 Divide by 2

2x/2 = 62/2

x = 31 <<<<< Answer

3 0

2 years ago