Answer:
27 feet
Step-by-step explanation:
Two walls have same area
Area of first wall(square) = 18*18 = 324
Area of second wall = 12 * x = 324
324/12 = 27
27 feet
I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
Answer:
See solutions below
Step-by-step explanation:
From the given diagram;
AC = opposite
AB = 7 = hypotenuse
Angle of elevation = 70 degrees
Using SOH CAH TOA
Sin theta = opp/hyp
Sin theta = AC/AB
Sin 70 = AC/7
AC = 7sin70
AC = 7(0.9397)
AC = 6.58
Similarly
tan 70 = AC/BC
tan 70 = 6.58/BC
BC = 6.58/tan70
BC = 6.58/2.7475
BC = 2.39
tan m<A = BC/AC
tanm<A = 2.39/6.58
tan m<A = 0.3632
m<A = 19.96degrees
Answer:
x can be any number
Step-by-step explanation:
because the two sides are equal x could be any number.