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attashe74 [19]
2 years ago
12

In circle E with m DGF = 27, find the mZDEF.

Mathematics
1 answer:
boyakko [2]2 years ago
4 0

Hope this help!!!

Have a nice day!!!

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louis makes a$15 [er hour working at the mall. which equation represents the total amout of money, d, louis makes in h hours?
emmainna [20.7K]

Answer:

15H = D

Step-by-step explanation:

Given that Louis makes $ 15 per hour working at the mall, to determine which equation represents the total amout of money, D, Louis makes in H hours, the following calculation must be performed:

15H = D

So, for example, if Louis worked 10 hours, the equation would operate as follows:

15 x 10 = D

150 = D

3 0
2 years ago
Tasha went golfing. Tasha hit the ball 220 yards down the fairway and then 165 yards to the hole. What would have been the short
steposvetlana [31]

Answer:

385 yards

Step-by-step explanation:

From the information provided we can only assume that the two hits that Tasha performed were in a straight line and in the same direction. Otherwise we would need to know the direction and/or angle of the shots. Assuming they were straight, the shortest minimum distance between the tee area and the hole would be calculated by adding the distance of the two shots.

220 yards + 165 yards = 385 yards

6 0
2 years ago
A cylinder with<br> a radius of 2<br> inches and height<br> of 8 inches
Gelneren [198K]

Answer:

V≈100.53

Step-by-step explanation:

V=πr2h=π·22·8≈100.53096

5 0
2 years ago
What multiplication problem is represented by the model?
Sophie [7]

Answer:

D last one.

Step-by-step explanation:

4x4=16 not 8

3 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
2 years ago
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