Given:
Triangles FRI and DAY are similar.
To find:
Similarity ratio
Solution:
<em>If two triangles are similar then the corresponding angles are congruent and the corresponding sides are in proportion.</em>
Here, FR and DA are corresponding sides.
Cancel the common factors of 4 and 6, we get
⇒ FR : DA = 2 : 3
⇒ ΔFRI : ΔDAY = 2 : 3
Similarity ratio of the first triangle to the second triangle is 2 : 3.
Answer:
D is the answers for the question
Step-by-step explanation:
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Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
