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4 years ago

What is the first answer to the first question

Mathematics

2 answers:

prohojiy [21]4 years ago

7 0

Answer:

2.99

Step-by-step explanation:

Mars2501 [29]4 years ago

4 0

All you need to do is do $23 divide by %13. (Which you are dividing 0.13 23.

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The two square pyramids are similar. The side length of the smaller pyramid is 3/4 the side length of the larger pyramid.Which f

vichka [17]

The answer is A.9/16.

The ratio of areas of two similar squares is the square of the ratios of their similar side lengths. Since the ratio of the smaller side length to the larger side length is 3/4, the ratio of areas of two similar squares is:
(3/4)² = 3²/4² = 9/16.

7 0

3 years ago

Read 2 more answers

Math question

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

3 years ago

Which of the following statements is the best definition of a triptych?

slega [8]

It might be a. A painting on three panels. I am not sure, so don't blame me if I get it wrong.

8 0

3 years ago

Can someone help me with this math homework please!

Ghella [55]

Answer:

$y=\frac{5}{2} \:x$

Step-by-step explanation:

A line with the highest absolute value of slope has the steepest graph

from the option, the highest is 5/2 so, y = 5/2 x is your answer.

OAmalOHopeO

3 0

3 years ago

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A recipe requires 1/2 cup of sugar for every batch of cakes. How batches of cakes can be made with 5 1/2 cups of sugar?

Sedaia [141]

Answer:

Step-by-step explanation:

5.5/.5 = 11

7 0

3 years ago

Read 2 more answers