The answer is <span>A.9/16.
The ratio of areas of two similar squares is the square of the ratios of their similar side lengths. Since </span><span>the ratio of the smaller side length to the larger side length is 3/4, the ratio of areas of two similar squares is:
(3/4)</span>² = 3²/4² = 9/16.
Answer:
The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.
Step-by-step explanation:
The volume (
), in cubic centimeters, and surface area (
), in square centimeters, formulas for the candle are described below:
(1)
(2)
Where:
- Radius, in centimeters.
- Height, in centimeters.
By (1) we have an expression of the height in terms of the volume and the radius of the candle:

By substitution in (2) we get the following formula:


Then, we derive the formulas for the First and Second Derivative Tests:
First Derivative Test



![r = \sqrt[3]{\frac{V}{2\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BV%7D%7B2%5Cpi%7D%20%7D)
There is just one result, since volume is a positive variable.
Second Derivative Test

If
:

(which means that the critical value leads to a minimum)
If we know that
, then the dimensions for the minimum amount of plastic are:
![r = \sqrt[3]{\frac{V}{2\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BV%7D%7B2%5Cpi%7D%20%7D)
![r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3217%5C%2Ccm%5E%7B3%7D%7D%7B2%5Cpi%7D%7D)




And the amount of plastic needed to cover the outside of the candle for packaging is:



The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.
It might be a. A painting on three panels.
I am not sure, so don't blame me if I get it wrong.
Answer:

Step-by-step explanation:
A line with the highest absolute value of slope has the steepest graph
from the option, the highest is 5/2 so, y = 5/2 x is your answer.
<u></u>
<u> OAmalOHopeO</u>