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3 years ago

A square banner has an area of 289 square inches.

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Easy take $\sqrt{289}$

in this case $\sqrt{289}$ =17

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Rectangle with a side length of 11" and a diagonal of 14" what is the perimeter

notka56 [123]

Answer:

10sqrt3+22

Step-by-step explanation:

Ok, let us imagine it as a sort of rectangle split upon its diagonal.

Using that, we can Pythag it out,

11^2+b^2=14^2

121+b^2=196

b^2=75

b=sqrt75

b=5sqrt3

Ok, using this info, we find the perimeter,

5sqrt3+5sqrt3+11+11

10sqrt3+22

The answer is 10sqrt3+22

7 0

3 years ago

Read 2 more answers

Find the missing angle measure in ΔABC.

Otrada [13]

The answer to your question is b

4 0

3 years ago

Micheal took his brother to the movies. Micheal paid regular price, but it cost $2 less for his brother at the child price. It c

iren [92.7K]

It cost $5 for his brother's ticket.

Step-by-step explanation:

Let,

Micheal's ticket price= x

His brother ticket price = y

According to given statement;

x+y=12 Eqn 1

y = x-2 Eqn 2

Putting value of y from Eqn 2 in Eqn 1

$x+(x-2)=12\\x+x-2=12\\2x=12+2\\2x=14\\$

Dividing both sides by 2;

$\frac{2x}{2}=\frac{14}{2}\\x=7$

Putting x=7 in Eqn 2

$y=7-2\\y=5$

It cost $5 for his brother's ticket.

Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

8.)What is the Measurement of angle 2?<br><br> 9.) What is the measure of angle 7?

EastWind [94]

Answer:

angle 2 = 90° {corresponding angles}

angle 7 + angle 5 = 180° {linear pair}

or, angle 7 + 100° = 180° {angle 5 is corresponding to 100°}

so, angle 7 = 80°

8 0

2 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

Read 2 more answers