Answer:
1115322
Step-by-step explanation:
In 1906, San Francisco felt the impact of an earthquake with a magnitude of 7.8.
Claimed statement is he worst is yet to come, with an earthquake 142,990 times as intense as the 1906 earthquake ready to hit San Francisco.
We need to find the magnitude of their claimed earthquake.
It can be calculated by simply multiplying 142,990 by 7.8 as follows :
The magnitude of claimed earthquake is 1115322
.
Answer:
r = m x h
Step-by-step explanation:
Answer:
x = 12
Step-by-step explanation:
Simplifying
6x + -2(-3x + -5) = 154
Reorder the terms:
6x + -2(-5 + -3x) = 154
6x + (-5 * -2 + -3x * -2) = 154
6x + (10 + 6x) = 154
Reorder the terms:
10 + 6x + 6x = 154
Combine like terms: 6x + 6x = 12x
10 + 12x = 154
Solving
10 + 12x = 154
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + 12x = 154 + -10
Combine like terms: 10 + -10 = 0
0 + 12x = 154 + -10
12x = 154 + -10
Combine like terms: 154 + -10 = 144
12x = 144
Divide each side by '12'.
x = 12
Simplifying
x = 12
Answer:
(I)Sin Θ=4/5
(II) Cos Θ =-3/5
(III) Tan Θ = -4/3
(IV) Cosec Θ = 5/4
(V) Sec Θ = -5/3
(VI) Cot Θ = -3/4
Step-by-step explanation:
(-24,18)
This lies in the second quadrant from the diagram.
Note that the angle is at the origin (0,0).
Using Pythagoras triples(18,24,30)
Hypotenuse = 30
Opposite=-24
Adjacent=18
(I)Sin Θ= Opposite/Hypotenuse
=-24/30=-4/5
Note: (Sine is Positive in the Second Quadrant)
Sin Θ =4/5
(II) Cos Θ = Adjacent/Hypotenuse
=18/30=3/5
Since Cosine is negative in the Second Quadrant
Cos Θ=-3/5
(III) Tan Θ = Opposite/Adjacent
Tan Θ = -24/18= -4/3
(IV) Cosec Θ = 1/Sin Θ = 5/4
(V) Sec Θ = 1/cos Θ = -5/4
(VI) Cot Θ = 1/tan Θ = -3/4