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SVEN [57.7K]
4 years ago
11

If you flip a fair coin 444 times, what is the probability that you will get exactly 222 tails?

Mathematics
2 answers:
Whitepunk [10]4 years ago
8 0

Answer:50%

Step-by-step explanation:

222+222=444 so as a fraction the probability is 1/2 but as a percentage its 50%

SVETLANKA909090 [29]4 years ago
3 0

Answer:

3/8

Step-by-step explanation:

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Triangle JKL is rotated 270° counterclockwise about the origin to form triangle J'K'L'.
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Triangle JKL was rotated 90° counterclockwise and then refrected across the line y = -4.

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3 years ago
each side of triangle xyz has length 9 .Find the area of the region inside the circumcircle of the triangle but outside the tria
mote1985 [20]

Answer:

The area of the region inside the circumcircle of the triangle but outside the triangle is

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the area of triangle

we have an equilateral triangle

Applying the law of sines

A_t=\frac{1}{2}(b^2)sin(60^o)

where b is the length side of the equilateral triangle

we have

b=9\ units

A_t=\frac{1}{2}(81)sin(60^o)

A_t=\frac{1}{2}(81)\frac{\sqrt{3}}{2}

A_t=81\frac{\sqrt{3}}{4}\ units^2

step 2

Find the area of circle

The area of the circle is equal to

A_c=\pi r^{2}

The formula to calculate the radius of the circumcircle of the triangle equilateral is equal to

r=b\frac{\sqrt{3}}{6}

where b is the length side of the equilateral triangle

we have

b=9\ units

substitute

r=(9)\frac{\sqrt{3}}{6}

r=3\frac{\sqrt{3}}{2}\ units

Find the area

A_c=\pi (3\frac{\sqrt{3}}{2})^{2}

A_c=\frac{27}{4} \pi\ units^2

step 3

Find the area of the shaded region

we know that

The area of the region inside the circumcircle of the triangle but outside the triangle is equal to the area pf the circle minus the area of triangle

so

A=(\frac{27}{4} \pi-81\frac{\sqrt{3}}{4})\ units^2

Simplify

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

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Answer:

10.5

Step-by-step explanation:

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The answer is -2 when you simplify
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