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zysi [14]
3 years ago
14

A boy travelled a distance of 10 km in 2 minutes calculate the speed of that boy ​

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

Step-by-step explanation:

(i hope this helps)

speed=distance/time taken

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Find an equation for the perpendicular bisector of the line segment whose endpoints
TEA [102]

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

\boxed{gradient =  \frac{y1 -y 2}{x1 - x2} }

Gradient of given line

=  \frac{1 - ( - 5)}{3 - ( - 9)}

=  \frac{1 + 5}{3 + 9}

=  \frac{6}{12}

=   \frac{1}{2}

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

\boxed{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2})  }

Midpoint of given line

= ( \frac{3  -  9}{2} , \frac{1 - 5}{2} )

= ( \frac{ - 6}{2}  , \frac{ - 4}{2} )

= ( - 3 , - 2)

Substituting (-3, -2) into the equation:

-2= -2(-3) +c

-2= 6 +c

c= -2 -6 <em>(</em><em>-</em><em>6</em><em> </em><em>on both</em><em> </em><em>sides</em><em>)</em>

c= -8

Thus, the equation of the perpendicular bisector is y= -2x -8.

5 0
3 years ago
SOMEONE HELP ME PLEASE QUESTION I'll give you the crown please someone help An equation using at least seven numbers and / or sy
stiv31 [10]

Answer:

7+9-4/2-7+21=28

Step-by-step explanation:

8 0
3 years ago
Find the amount and present value of 10 quarterly payments of $ 1500, if the interest rate is 25% compounded each month.
BlackZzzverrR [31]

Given Information:

Monthly payment = MP = $1500/4 = $375

Monthly interest rate = r = 25/12 = 2.083%

Required Information:

Present Value = ?

Answer:

PV = \$10,110

Explanation:

n = 10*4

n = 40 monthly payments

The present value is found by

$ PV = MP \times  \frac{ (1 - \frac{1}{(1+r)^n} )}{r}  $

Where r is monthly interest rate.

MP is the monthly payment.

$ PV = 375 \times  \frac{ (1 - \frac{1}{(1+0.02083)^{40}} )}{0.02083}  $

PV = 375 \times (26.96)

PV = \$10,110

Therefore, $10,110 is the present value of 10 quarterly payments of $1500 each at 25% interest rate compounded each month.

7 0
3 years ago
Find the acute angle between the lines. round your answer to the nearest degree. 6x − y = 4, 4x y = 9
garri49 [273]
Picture please and thank you

8 0
2 years ago
Given vectors a=(-1,-2), b=(-2,3), c=(3,-1), d=(-3,2) find the dot product of b and d.
goldfiish [28.3K]

hope it helps u.........

6 0
3 years ago
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