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soldier1979 [14.2K]
3 years ago
12

A sand volleyball court has an area of 162 square meters and a perimeter of 54 meters. What are the dimensions of the volleyball

court?
Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0
I honestly dont know how to figure this one out.
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The answer to c plz
NikAS [45]

Answer:

≈ 30.63 cm²

Step-by-step explanation:

The shaded area is calculated by subtracting the area of the inner circle from the area of the outer circle.

outer circle has radius = 8 ÷ 2 = 4 and inner circle has radius = 5 ÷ 2 = 2.5

shaded area = πr₁² - πr₂² (r₁ is outer and r₂ is inner )

A = π (4² - 2.5²)

   = π(16 - 6.25) = 9.75π ≈ 30.63 cm²

           

5 0
3 years ago
How to add and subtract radical expressions
Ivanshal [37]
Subtract them left to right

4 0
3 years ago
Identify the values of the variables. Give your answers in simplest radical form. HELP ASAP!!
kumpel [21]

Answer:

B

Step-by-step explanation:

Since the triangle is right use the sine/ tangent ratios to solve for x and y

note sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3}

sin60° = \frac{opposite}{hypotenuse} = \frac{3\sqrt{6} }{y}

ysin60° = 3\sqrt{6}

y × \frac{\sqrt{3} }{2} = 3\sqrt{6}

multiply both sides by 2 and divide by \sqrt{3}

y v= 6\sqrt{\frac{6}{3} } = 6\sqrt{2}

tan60° = \frac{opposite}{adjacent} = \frac{3\sqrt{6} }{x}

xtan60° = 3\sqrt{6}

x × \sqrt{3} = 3\sqrt{6}

divide both sides by \sqrt{3}

x = 3\sqrt{\frac{6}{3} } = 3\sqrt{2}


8 0
3 years ago
Read 2 more answers
PLEASE HELP ME I NEED TO FINISH THIS!!!
egoroff_w [7]

Answer:

2, 1, 1/2, 1/4

Step-by-step explanation:

2¹ = 2

2^0 = 1

2^-¹

= 1/2¹

= 1/2

2^-2

= 1/2²

= 1/2*2

= 1/4

To complete the table

2² 2¹ 2^0 2^-1 2^-2

4 2 1 1/2 1/4

5 0
3 years ago
Mrs. Miller wants to estimate the widths the steps in front of her house . Best bench mark for her to use is ?
Arisa [49]
The best bench mark to use is an inch. She should use an inch because centimeters are too small and the steps might be less than a foot.
7 0
3 years ago
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