Question 1 of 10

Mathematics

1 answer:

AURORKA [14]3 years ago

6 0

Answer:

the answer is going to be b

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Which shows only a vertical translation from the shaded figure onto the unshaded figure?

sergiy2304 [10]

Answer: Its A Im pretty sure

Step-by-step explanation:

5 0

3 years ago

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What is the determinant of the coefficient matrix of this system? 4x-3y=-8 8x-3y=12

gladu [14]

The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.

So, you may write the matrix as

$\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\\\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]$

which means

$\left[\begin{array}{cc}4&-3\\8&-3\end{array}\right]$

The determinant is computed subtracting diagonals:

$\left | \left[ \begin{array}{cc}a&b\\c&d\end{array}\right]\right | = ad-bc$

So, we have

$\left | \left[\begin{array}{cc}4&-3\\8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12$

8 0

3 years ago

Help mee

Artist 52 [7]

1. Add all of the numbers together
2. Divide the answer by how many different numbers there are (so 10)
The mean to the nearest tenth is 356.8

6 0

3 years ago

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How to write an equation of a horizontal line through a point?

satela [25.4K]

Y= y1

replace the y1 with the ordinate ( the y-part) of the point you are going thru

example a horizontal line going through the point (7,12) would be y=12

3 0

3 years ago

FIND THE THIRD,FIFTH AND TENTH TERM SEQUENCE DESCRIBED BY EACH RULE

Karolina [17]

In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

THIRD
A3=4+(3-1)(-5)
A3 = -6

A(3)=-2(3-1)(-5)
A3 = 20

FIFTH
A5=4+(5-1)(-5)
A5 = -16

A(5)=-2(5-1)(-5)
A5 = 40

TENTH
A10=4+(10-1)(-5)
A10 = -41

A(10)=-2(10-1)(-5)
A10 = 90

8 0

3 years ago