Question 1 of 10

6/5 ÷ ____ = 6 A. 1/5 B. 30 C. 1/30 D. 5

murzikaleks [220]

Answer:

A. $\displaystyle \frac{1}{5}$

Step-by-step explanation:

$\displaystyle \frac{6}{5} \div \frac{1}{5} = 6 \\ \\ OR \\ \\ \frac{6}{5} \div 6 = \frac{1}{5}$

I am joyous to assist you anytime.

4 0

3 years ago

In triangle RST, angle R is a right angle. If TR = 6 and TS = 8, what is the length of RS

lisabon 2012 [21]

Answer:

RS = 2 $\sqrt{7}$

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

RS² + RT² = TS² , that is

RS² + 6² = 8²

RS² + 36 = 64 ( subtract 36 from both sides )

RS² = 28 ( take the square root of both sides )

RS = $\sqrt{28}$ = $\sqrt{4(7)}$ = 2 $\sqrt{7}$ ≈ 5.3 ( to 1 dec. place )

8 0

3 years ago

Select all the correct answers.

ohaa [14]

Answer:

Lines 3 and 4

Step-by-step explanation:

ignore this rjrjrjrjrrnrnnrnrrnnr

8 0

3 years ago

I need help with question 15

Nadusha1986 [10]

A rational number is a number that can be written in the form:

$\frac{p}{q}$

Where p and q are coprimes. We are asked for finite sets, we can rule out options 3 and 4. In the set in option 2 the first element is:

$\sqrt{3}$

This number cannot be written a ratio. We can rule out option 2.

All the elements in the set from option 1 can be written in the form p/q.Thus, the answer is the first option.

3 0

1 year ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago