Answer:
![\boxed{ \bold{ \huge{ \boxed{ \sf{ \sqrt{130} \: \: units}}}}}](https://tex.z-dn.net/?f=%20%20%5Cboxed%7B%20%5Cbold%7B%20%5Chuge%7B%20%5Cboxed%7B%20%5Csf%7B%20%5Csqrt%7B130%7D%20%20%5C%3A%20%20%5C%3A%20%20units%7D%7D%7D%7D%7D)
Step-by-step explanation:
Let the points be A and B
Let A ( 1 , 3 ) be ( x₁ , y₁ )and B ( -6 , -6 ) be ( x₂ , y₂ )
<u>Finding </u><u>the </u><u>distance</u><u> </u><u>between </u><u>these</u><u> </u><u>points</u>
![\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%7Bdistance%20%3D%20%20%5Csqrt%7B%20%7B%28x2%20-%20x1%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%28y2%20-%20y1%29%7D%5E%7B2%7D%20%7D%20%7D%7D)
![\longrightarrow{ \sf{ \sqrt{ {( - 6 - 1)}^{2} + {( - 6 - 3)^{2} } }}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5Csqrt%7B%20%7B%28%20-%206%20-%201%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%206%20-%203%29%5E%7B2%7D%20%20%7D%20%7D%7D%7D)
![\longrightarrow{ \sf{ \sqrt{ {( - 7)}^{2} + {( - 9)}^{2} } }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5Csqrt%7B%20%7B%28%20-%207%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%209%29%7D%5E%7B2%7D%20%20%7D%20%7D%7D)
![\longrightarrow{ \sf{ \sqrt{49 + 81}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5Csqrt%7B49%20%2B%2081%7D%7D%7D%20)
units
Hope I helped!
Best regards! :D
Answer: (-2,25)
Step-by-step explanation:
Answer::.x=6,y=2
3x - 5y = 8......(1)
X - 5y = - 4......(2)
subtracting equation 2 from 1 we get
Step-by-step explanation:
3x - 5y = 8
X - 5y = - 4
-
------------------
2x=12
x=12/2=6
multiplying equation 2 by3 weget
3x-15y=-12........(3)
subtracting equation 1from 3
3x-15y=-12
3x-5y=8
-
------------------
-10y=-12-8
y=-20/-10=2
<span>857/45 as a mixed number is </span>19 2/45
You can do it this think and if you can't I will help you