Complete the function using the function y=-2x -6<br> -2<br> 0<br> 2<br> 4

Solve the formula 4x+7y=9 for y.

satela [25.4K]

X=0.5
y=1

(4x0.5) + (7x1) = 9
2 + 7 = 9

5 0

2 years ago

Solve the for the inequality

Naddika [18.5K]

Answer:

k ≥ -18

Step-by-step explanation:

$-8\leq \frac{2}{5}(k-2)\\\\-8(5)\leq (5)\frac{2}{5}(k-2)\\\\-40\leq 2(k-2)\\\\\frac{-40}{2}\leq \frac{2(k-2)}{2}\\\\-20\leq k-2\\\\-20+2\leq k-2+2\\\\-18\leq k$

5 0

3 years ago

Read 2 more answers

Anthony bought an 8 foot board. He cut off 3/4 off the board to build a shelf and gave 1/3 of the rest to his brother for an art

Zina [86]

8 inches. 3/4 of 8 feet is 6 feet leaving two left over, one third of that is 8 inches.

6 0

3 years ago

Read 2 more answers

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(c) $\displaystyle P(B) = \frac{9}{100}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

Factor the expression. 2x^2-7x-15

lutik1710 [3]

Answer:

Factor by grouping

(2x+3) (x-5)

Step-by-step explanation:

3 0

3 years ago

Complete the function using the function y=-2x -6 -2 0 2 4