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expeople1 [14]
3 years ago
11

A right triangle has a leg of 12 cm and a hypotenuse of 19 cm.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

14.7 cm

Step-by-step explanation:

Using Pythagoras Theorem,

The length of the other leg

=  \sqrt{ {19}^{2}  -  {12}^{2} }

=  \sqrt{217}

= 14.730919...

= 14.7 cm (rounded to the nearest tenth)

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A rectangular field has an area 28800 sq meter. Its length is twice as long as its width. What is the length of its sides?
mina [271]
W= width L= length = 2W

Area of Rectangle= Length * Widthsubstitute the area and the value of L in the formula
28,800 m^2= 2W * W
28,800= 2W^2divide both sides by 2 in an effort to isolate the variable w
14,400= W^2take the square root of both sides
√14,400= W^2
we want the negative and positive root of the radicand (the number under the radical symbol - 14,400 in this case)
120= w OR -120= w


LENGTHL= 2W= 2(120)= 240 meters

ANSWER: The side lengths are W= 120 m; L= 240 m.  Even though W= -120 too, it is not a valid solution in this case since a field cannot have a negative value.

Hope this helps!  :)
3 0
3 years ago
hapis has four buckets. The buckets hold 4700ml,4.8l,3880ml,and 4.71 l hapis wants to to use the bucket that holds the closest t
Mariana [72]

Answer:

Bucket 2

Step-by-step explanation:

Bucket 1 = 4700ml

Bucket 2 = 4.8l

Bucket 3 = 3880ml

Bucket 4 = 4.71 l

Convert holding capacity of bucket 1 and bucket 3 into liters

1 liter = 1000 milliliter

Bucket 1 = 4700ml

4700ml = 4.7l

Bucket 3 = 3880ml

3880ml = 3.88l

Therefore,

Bucket 1 = 4.7l

Bucket 2 = 4.8l

Bucket 3 = 3.88l

Bucket 4 = 4.71 l

The bucket closest to 5liters is bucket 2 with a holding capacity of 4.8 liters

4 0
2 years ago
A plastic box has a length 4 cm longer than its width. The area of the rectangular top of the box is 77 square cm. Find the leng
finlep [7]

Answer: the length is 11 cm.

The width is 7 cm.

Step-by-step explanation:

Let L represent the length of the rectangular plastic box.

Let W represent the width of the rectangular plastic box.

The area of the rectangular top of the box is 77 square cm. This means that

LW = 77- - - - - - - ;- - - -1

The plastic box has a length 4 cm longer than its width. This means that

L = W + 4

Substituting L = W + 4 into equation 1, it becomes

(W + 4)W = 77

W² + 4W = 77

W² + 4W - 77 = 0

W² + 11W - 7W - 77 = 0

W(W + 11) - 7(W + 11) = 0

W - 7 = 0 or W + 11 = 0

W = 7 or W = - 11

Since the width cannot be negative, then W = 7cm

L = 77/7 = 11 cm

4 0
3 years ago
I need help with my math problem #6
guajiro [1.7K]
C) 93 
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3 years ago
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Number 10 is d and i’ll try 9 give me a minute lol
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