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jonny [76]
4 years ago
7

PLEASE HELP WILL GIVE BRAINLIEST!!!!!1

Mathematics
1 answer:
Murrr4er [49]4 years ago
4 0

Hey there!

<em>C = 0.25x + 40</em>

(a) For this part we solve for C when x = 240. Substitute 240 in for x.

C = 0.25(240) + 40

Multiply 240 by 0.25.

C = 60 + 40

Add.

C = 100

The cost is $100.

<u>Check</u>

100 = 0.25(240) + 40

100 = 60 + 40

100 = 100

(b) For this part we solve for x when C = 180. Substitute 180 for C.

180 = 0.25x + 40

Subtract 40 from each side.

140 = 0.25x

Divide each side by 0.25.

560 = x

This person drove 560 miles.

<u>Check</u>

180 = 0.25(560) + 40

180 = 140 + 40

180 = 180

(c) For this we must make an inequality with C = 150.

Since they want the cost to be <em>no more than</em> 150, we will use the ≥ symbol.

C ≥ 0.25x + 40

Substitute 150 for C. Solve for x.

150 ≥ 0.25x + 40

Subtract 40 from each side.

110 ≥ 0.25x

Divide each side by 0.25.

440 ≥ x

The max number of miles they can drive is 440.

<u>Check</u>

150 ≥ 0.25(440) + 40

150 ≥ 110 + 40

150 ≥ 150

Hope this helps!

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Inessa05 [86]

The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).

The equation 121b⁴ − 49

To find the Factorization of 121b⁴ − 49.

<h3>What is the factor of a^2-b^2?</h3>

The factor of a^2-b^2 is  (a+b)(a-b)

We have write the given equation in the form of a^2-b^2

= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).

To learn more about the factor visit:

brainly.com/question/25829061

5 0
2 years ago
Find compound interest on12600rupees for 2years at10% per annum compounded anually<br>​
vekshin1

Answer:

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Step-by-step explanation:

First, converting R percent to r a decimal

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then, solving our equation

I = 12600 × 0.1 × 2 = 2520

I = ₹ 2,520.00

The simple interest accumulated

on a principal of ₹ 12,600.00

at a rate of 10% per year

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