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Margarita [4]
3 years ago
9

Which statement is true?

Mathematics
1 answer:
NeTakaya3 years ago
7 0
D. Hope this helps :))
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I have a square with a side of 5.25 in. There is a circle inside this square that is big enough to touch all four sides. What is
DENIUS [597]

Answer:

5.9125in^2

Step-by-step explanation:

Step one:

Given data

Dimension of square= 5.25 in

Area of sqaure= 5.25^2= 27.5625  in^2

We are told that the sides of the circle touch the sides of the square

hence the diameter of the circle is 5.25in

radius= 5.25/2= 2.625 in

Area of  circle= πr^2

Area of circle = 3.142*2.625^2

Area of circle=3.142*6.890625

Area of circle= 21.65 in^2

Step two:

The area that is not inside the circle

=Area of square-Area of circle

=27.5625- 21.65

=5.9125in^2

4 0
3 years ago
(5x10^7)(6x10^4) in scientific notation
Ratling [72]

Answer:

(5 x 10^7)(6 x 10^4)= 3 x 10^12 is the answer in scientific notation

Step-by-step explanation:

5 0
3 years ago
F(x)=-x^2+3 find f(-2)
Black_prince [1.1K]

Answer:

f(-2) = -1

Step-by-step explanation:

f(x) = -x^2 + 3

f(-2) means when x is -2

Shown in the graph below, the point of solution is: (-2,-1), so when x is -2 y is -1

8 0
3 years ago
In a certain​ chemical, the ratio of zinc to copper is 3 to 17. A jar of the chemical contains 799 grams of copper. How many gra
dezoksy [38]

Answer:

let's see what to do buddy...

Step-by-step explanation:

\frac{zinc}{copper} =  \frac{3}{17} \\  \\  \frac{zinc}{799} =  \frac{3}{17}

Multiply the sides of the equation by 799

zinc =  \frac{3}{17} \times 799 \\ \\ zinc =  \frac{3}{17} \times 17 \times 47 \\ \\  zinc = 3 \times 47 = 141

So A jar of the chemical contains 141 grams of <em><u>zinc</u></em>.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
3 years ago
Absolute value of |x|= 5\6
12345 [234]

Hey there!☺

Answer:\boxed{x=\frac{5}{6},-\frac{5}{6}}

Explanation:

|x|=\frac{5}{6}

To solve for x, simplify both sides of the equation and then isolate the variable:

|x|=\frac{5}{6}\\x=\frac{5}{6},-\frac{5}{6}

Hope this helps!☺

4 0
3 years ago
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