All categories

3 years ago

Which statement is true?

Mathematics

1 answer:

NeTakaya3 years ago

7 0

D. Hope this helps :))

You might be interested in

I have a square with a side of 5.25 in. There is a circle inside this square that is big enough to touch all four sides. What is

DENIUS [597]

Answer:

5.9125in^2

Step-by-step explanation:

Step one:

Given data

Dimension of square= 5.25 in

Area of sqaure= 5.25^2= 27.5625 in^2

We are told that the sides of the circle touch the sides of the square

hence the diameter of the circle is 5.25in

radius= 5.25/2= 2.625 in

Area of circle= πr^2

Area of circle = 3.142*2.625^2

Area of circle=3.142*6.890625

Area of circle= 21.65 in^2

Step two:

The area that is not inside the circle

=Area of square-Area of circle

=27.5625- 21.65

=5.9125in^2

4 0

3 years ago

(5x10^7)(6x10^4) in scientific notation

Ratling [72]

Answer:

(5 x 10^7)(6 x 10^4)= 3 x 10^12 is the answer in scientific notation

Step-by-step explanation:

5 0

3 years ago

F(x)=-x^2+3 find f(-2)

Black_prince [1.1K]

Answer:

f(-2) = -1

Step-by-step explanation:

f(x) = -x^2 + 3

f(-2) means when x is -2

Shown in the graph below, the point of solution is: (-2,-1), so when x is -2 y is -1

8 0

3 years ago

In a certain chemical, the ratio of zinc to copper is 3 to 17. A jar of the chemical contains 799 grams of copper. How many gra

dezoksy [38]

Answer:

let's see what to do buddy...

Step-by-step explanation:

$\frac{zinc}{copper} = \frac{3}{17} \\ \\ \frac{zinc}{799} = \frac{3}{17}$

Multiply the sides of the equation by 799

$zinc = \frac{3}{17} \times 799 \\ \\ zinc = \frac{3}{17} \times 17 \times 47 \\ \\ zinc = 3 \times 47 = 141$

So A jar of the chemical contains 141 grams of <em><u>zinc</u></em>.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0

3 years ago

Absolute value of |x|= 5\6

12345 [234]

Hey there!☺

$Answer:\boxed{x=\frac{5}{6},-\frac{5}{6}}$

$Explanation:$

$|x|=\frac{5}{6}$

To solve for x, simplify both sides of the equation and then isolate the variable:

$|x|=\frac{5}{6}\\x=\frac{5}{6},-\frac{5}{6}$

Hope this helps!☺

4 0

3 years ago