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Margarita [4]
3 years ago
9

Which statement is true?

Mathematics
1 answer:
NeTakaya3 years ago
7 0
D. Hope this helps :))
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Construct the cumulative frequency distribution for the given data.
tino4ka555 [31]

Answer:

       Age                               Frequency                   Cumulative Frequency

 Less than 30                             27                                       27

 Less than 40                             37                                27 + 37  =  64

 Less than 50                              1 1                                 64 + 11   =  75

 Less than 60                               3                                  75 + 2   =  77

 Less than 70                               5                                   77 + 5   =  82

 Less than 80                               1                                     82 + 1  =  83

 Less than 90                              2                                    83 +2  =  85

Step-by-step explanation:

Given:

The Frequency Distribution table of ages of best actresses when award was won

To find:

Construct the cumulative frequency distribution

Solution:

In order to construct cumulative frequency distribution for the given data, each frequency from above table is added to the sum of the previous frequencies. For example, frequency for Less than 40  is 37 and the previous frequency (less than 30) is 27 so in order to calculate cumulative frequency 27 i.e. previous frequency is added to 37 (frequency of less than 30). The complete table is given above.

4 0
3 years ago
Which are the solutions of x2 = 19x + 1?
Finger [1]

Answer:

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

Step-by-step explanation:

we have

x^2=19x+1

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2}-19x-1=0  

so

a=1\\b=-19\\c=-1

substitute in the formula

x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}

x=\frac{19\pm\sqrt{365}} {2}

x=\frac{19+\sqrt{365}} {2}

x=\frac{19-\sqrt{365}} {2}

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0
3 years ago
Read 2 more answers
8. | 11 | 14 | 17 | 20<br> What’s the function
Murrr4er [49]

Answer:

What do you exactly need to do?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3
Mama L [17]

Answer:

\displaystyle x=-\frac{1}{6}, 3

Step-by-step explanation:

Hi there!

y = 6x^2 - 17x - 3

Factor by grouping:

y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)

Let y=0. Apply the zero product property:

0 = (6x+1)(x- 3)

6x+1=0\\6x=-1\\\\\displaystyle x=-\frac{1}{6}

AND

x-3=0\\x=3

I hope this helps!

5 0
3 years ago
A positive integer squared plus 3 times it’s consecutive integer is equal to 43
Eduardwww [97]

Answer:

the integer is 5

Step-by-step explanation:

x^2+3(x+1)=43

x^2+3x+3=43

x^2+3x+(9/4)=43-3+(9/4)

(x+(3/2))^2=42 1/4

x+(3/2)=sqrt(42 1/4)

x+(3/2)=6 1/2

x=(6 1/2)-(3/2)

x=5

check:

5^2+3(6)=43

25+18=43

43=43

3 0
2 years ago
Read 2 more answers
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