2 years ago

The red dots mean there is an empty place to put the answer Options at the bottom.

Mathematics

1 answer:

givi [52]2 years ago

8 0

Answer:

1 Multi

20 identity

Step-by-step explanation:

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

2 years ago

1.2 as a fraction with a denominator of 8

Aleks04 [339]

The answer is 1 whole and 1 /18. Hope this helps!

3 0

3 years ago

I need help on math on how to solve a linear equation. So how do you solve (x-2)+(2x+5).

saveliy_v [14]

So, put your "x's" together first and then your intercepts. That should answer your question :)

4 0

2 years ago

List multiples of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D" id="TexFormula1" title="\frac{5}{8}" alt="\frac{5}{8}

Mila [183]

Answer:

5/8

10/8 = 1 2/8 = 1 1/4

15/8 = 1 7/8

20/8 = 2 4/8 = 2/1/2

Step-by-step explanation:

DO NOT multiply both the numerator and the denominator by the same value.

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2 years ago

A rectangular tile has a decorative pattern of 3 equal-sized squares, each of which is divided into 2 same-sized triangles. If M

Andrew [12]

72 triangles will be displayed I believe....

All you do is multiply 2 times 36 and you get 72. Because there are 2 triangles in one square, so 2*36.

Hope this Helps!

8 0

3 years ago

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