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Novosadov [1.4K]
3 years ago
14

The width of a rectangle is six meters less than three times its length. If the area of the rectangle is 105 square meters. what

is the length
Mathematics
1 answer:
Kipish [7]3 years ago
7 0

Answer:

length = 7 meters

Step-by-step explanation:

l = length

w = width

w = 3×l - 6

l×w = 105 m²

l×(3×l - 6) = 105

3×l² - 6×l = 105

l² - 2×l = 35

l² - 2×l - 35 = 0

solution of a squared equation is

(-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = -2

c = -35

(2 ± sqrt(4 - 4×-35))/2 = (2 ± sqrt(4+140))/2 =

(2 ± sqrt(144))/2 = (2 ± 12)/2 = 1 ± 6

l1 = 1+6 = 7 meters

l2 = 1-6 = -5 meters, which did not make any sense for an actual object.

so, l = 7 meters remains.

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a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
ASAP PLS
Wittaler [7]

Assuming Earth's gravity, the formula for the flight of the particle is: 


s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. 


This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2. 


Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet. 




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