Given:
M=(x1, y1)=(-2,-1),
N=(x2, y2)=(3,1),
M'=(x3, y3)= (0,2),
N'=(x4, y4)=(5, 4).
We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.
For a parallelogram, opposite sides are equal
If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.
To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,
Slope of MN= Slope of M'N'.
Slope of MM'=NN'.

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.
Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.
Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.
To answer this question, you can use a factor tree, or the table thing (I forgot what it’s called.)
You divide the number by one of its PRIME factors, until there is only one left. The numbers you divided it by are written as shown.
Hope this helps. :)
Answer:
0.9375
Step-by-step explanation:
Do the long division and you'll find the answer.
The answer would be C) because there are 11 possibilities of who can line up first, and after the first person, 10 possibilities, then 9, and so on. So you would need to multiply 11x10x9x8x...x1.