Answer: 86.64%
Step-by-step explanation:
Let x be a random variable that represents the diameter of metal samples.
Given : Population mean : 
Standard deviation: 
Specified tolerance on the diameter is 0.75 mm.
i.e. range of diameter = 10-0.75< x <10+0.75 = 9.25< x< 10.75
Formula to find the z-score corresponds to x: 
At x= 0.75, 
Using standard normal table for z-value,
P-value : 
∴ Percentage of samples manufactured using this process satisfy the tolerance specification = 86.64%
Answer:
Step-by-step explanation:
so you already have the formula, which is
![\sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
the v represents Volume.
and 3v would be 3×volume.
![\sqrt[3]{ \frac{3 \times 1000}{4 \times \pi} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%201000%7D%7B4%20%5Ctimes%20%5Cpi%7D%20%7D%20)
![\sqrt[3]{ \frac{3000}{12.56637061} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3000%7D%7B12.56637061%7D%20%7D%20)
![\sqrt[3]{238.7324147 }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B238.7324147%20%7D%20)
to the nearest tenth place.
Answer:
First one: C. Second One:C.
Step-by-step explanation:
Kate purchased a car for $23,000. It will depreciate by a rate of 12% a year. What is the value of the car in 4 years?
a) $13,935.76
b) $12,874.57
c) $13,792.99
To solve this this is an exponential function. The price started at $23,000 and depreciates at 12% so the equation is f(x) = (23,0000)(1-0.12)^4. When calculated results with 13792.99328 which is C.
A rare coin is currently worth $450. The value of the coin increases 4% each year. Determine the value of the coin after 7 years.
a) $613.98
b) $546.78
c) $592.17
To solve this this is also an exponential function. The price started at $450 and the coin increases 4% each year so the equation is f(x) = (450)(1+0.04)^7. When calculated results with 592.169300656 which is c.
Hi mate!
The answer after simplifying is: 2x^2-6x+7
Please let me know if you need further assistance! Have a terrific evening.
~Brooke❤️
