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charle [14.2K]
3 years ago
10

For the equilibrium 2 NOBr(g) D 2 NO(g) + Br2(g), Kc = 1.56 ´ 10-3 at 300 K. Suppose 0.400 M NOBr is placed in a reaction vessel

at 300 K. At a given point, the concentration of Br2 is 0.0134 M. Which of the following statements is true? The value of K will decrease until it is equal to Q. Q < K so the reaction will continue to make more products. Q > K so the reaction will consume products to make more reactants. The value of K will increase until it is equal to Q. Q = K so the system is at equilibrium.
Chemistry
1 answer:
kicyunya [14]3 years ago
5 0

Explanation:

2 NOBr(g) ⇄ 2 NO(g) + Br2(g)

Kc = 1.56 ´ 10-3

Which of the following statements is true?

The reaction quotient (Q) measures the relative amounts of products and reactants present during a reaction at a particular point in time. The Q value can be compared to the Equilibrium Constant, K, to determine the direction of the reaction that is taking place.

- The value of K will decrease until it is equal to Q: This statement is wrong.

Equilibrium constants are not changed if you change the concentrations of things present in the equilibrium. The only thing that changes an equilibrium constant is a change of temperature.

- Q < K so the reaction will continue to make more products.

If Q<K, then the reaction favors the products. the system shifts to the RIGHT to make more products. This statement is true.

- Q > K so the reaction will consume products to make more reactants.

If Q>K, then the reaction favors the reactants. the system shifts to the LEFT to make more reactants. This statement is true.

- The value of K will increase until it is equal to Q: This statement is wrong.

Equilibrium constants are not changed if you change the concentrations of things present in the equilibrium. The only thing that changes an equilibrium constant is a change of temperature.

- Q = K so the system is at equilibrium: This statement is true.

If Q=K, then the reaction is already at equilibrium. There is no tendency to form more reactants or more products at this point. No side is favored and no shift occurs.

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What value of ℓℓ is not allowed for an electron in an n = 3 shell?
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Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te
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Answer:

n_{N_2}=6.41mol

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol

Quiere decir que las moles de N2(g) que se agregaron son:

n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol

¡Saludos!

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Answer: 3.59

Explanation:

(2.06)(1.743)(1.00)

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= 3.59058

Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.

3.59058 to 3 significant figures:

First three digits = 3.59

Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits

Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :

3.59

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