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Vinil7 [7]
3 years ago
12

This type of substance has a pH of 7. It will not change the color of litmus.

Chemistry
1 answer:
kvv77 [185]3 years ago
5 0
They do be needing more points tho lol
You might be interested in
Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
mash [69]

Answer:

              10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

   H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH  →  H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

    88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) Ethyl Butyrate

So,

           8.25 g Butanoic Acid will produce  =  X g of Ethyl Butyrate

Solving for X,

                      X =  (8.25 g × 116.16 g) ÷ 88.11 g

                      X =  10.87 g of Ethyl Butyrate

8 0
3 years ago
Torrey's neighbor told her that a marble rolling down a hill increases in velocity as it rolls down, but does not increase in ki
ziro4ka [17]

Answer:

Torrey's neighbour is incorrect because increase in kinetic energy is proportional to velocity.  If the velocity increases so will the object's kinetic energy.  Because the mass is constant, if the velocity increases, so does the kinetic energy.

6 0
3 years ago
Que enuncia la ley de la conservación de la energia​
Flauer [41]

english:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

spanish:

En física y química, la ley de conservación de la energía establece que la energía total de un sistema aislado permanece constante; se dice que se conserva con el tiempo.

3 0
2 years ago
Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0
olya-2409 [2.1K]

Answer:

pH=-1.37

Explanation:

We are given that 25 mL of 0.10 M CH_3COOH is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of CH_3COOH=25mL=0.025 L

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL=\frac{35}{1000}=0.035 L

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of CH_3COOH=0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+=0.10\times 0.025=0.0025 moles

Number of moles of OH^-=0.10\times 0.01=0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+=\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L

pH=-log [H+]=-log [4.28\times 10^{-2}]=-log4.28+2 log 10=-0.631+2

pH=-1.37

6 0
3 years ago
The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o
meriva

Answer:

\boxed{-267.5}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹   219.5      205.0         213.6         69.9

\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}

3 0
3 years ago
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