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scoundrel [369]
3 years ago
5

Electrons have what charge?

Chemistry
2 answers:
olchik [2.2K]3 years ago
7 0
Negative charge. hope this helps
Olin [163]3 years ago
5 0

Answer:

negative charge

Explanation:

protons have a positive, nuetrons have a neutral charge , and electrons have a negative.

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Chemical weathering occurs faster in warm, tropical climates, although it happens in cold climates as well. Describe some condit
andrew11 [14]

Oxidation, Dissolving in acid, Hydrolysis ,Water absorption and Hydration

6 0
2 years ago
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127) Thirty-six colonies grew in nutrient agar from 1.0 ml of undiluted sample in a standard plate count. How many cells were in
SIZIF [17.4K]

Answer:

36

Explanation:

Since the sample was undiluted the number of colonies is the number that grew on the nutrient agar which is 36 colonies. If it was diluted for example let say 0.1 ml from a dilution in which 1 ml of the sample was added to 9 ml of water, and it grew  colonies then  0.1 ml  yielded  6 colonies, 1 ml of the diluted sample will yield 60 colonies and 10 ml will have 600 colonies and therefore the 1 ml undiluted sample will have 600 colonies.

6 0
3 years ago
Balance and classify this reaction:<br> C6H6 +02 →CO2 +H₂O
laila [671]
This is a combustion reaction.
2C6H6 + 9O2➡️ 6CO2 + 6H2O
6 0
2 years ago
Answer only if you <br> had/have braces how long did it take to notice change with your braces on
AleksAgata [21]

Answer:

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Explanation:

8 0
3 years ago
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The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
3 years ago
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