Answer:
see below
Explanation:
16. 1 P₄(s) + 6 F₂(g) → 1 PF₃(s)
17. 2 C(s) + 2 H₂O(g) → 1 CH₄(g) + 1 CO₂(g)
18. 2 HgO(s)→ 1 O₂(g) + 2 Hg(l)
19. 1 CaCO₃(s) → 1 CO₂(g) + 1 CaO(s)
In all chemical equations, regardless of the type of reaction that is occurring, the reagents that are on the left side of the arrow are the reactants and on the right your products.
B. Is the solution.
I think its A. because there are nuclear fusion and nuclear fission
Answer:
It will take 3.3 s for [NOCl] to decrease to 0.042 M.
Explanation:
Integrated rate law for this second order reaction-
![\frac{1}{[NOCl]}=kt+\frac{1}{[NOCl]_{0}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BNOCl%5D%7D%3Dkt%2B%5Cfrac%7B1%7D%7B%5BNOCl%5D_%7B0%7D%7D)
where, [NOCl] is concentration of NOCl after "t" time, ![[NOCl]_{0}](https://tex.z-dn.net/?f=%5BNOCl%5D_%7B0%7D)
is initial concentration of NOCl and k is rate constant.
Here, = 0.076 M, k = 3.2 
and [NOCl] = 0.042 M
So, ![\frac{1}{0.042M}=[3.2M^{-1}s^{-1}\times t]+\frac{1}{0.076M}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.042M%7D%3D%5B3.2M%5E%7B-1%7Ds%5E%7B-1%7D%5Ctimes%20t%5D%2B%5Cfrac%7B1%7D%7B0.076M%7D)
or, t = 3.3 s
So, it will take 3.3 s for [NOCl] to decrease to 0.042 M.
Answer:
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