Pythagorean Theorem: a^2 + b^2 = c^2
a = 6
c = 9
b = ?
6^2 + b^2 = 9^2
36 + b^2 = 81
b^2 = 81 - 36
b^2 = 45
b = sqrt(45)
b = 6.71 miles
Given:
Atul has 
lb of candy.
Jose has 
lb of candy.
Maria has 
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has lb less than Jose, therefore
Maria has = 
lb
Maria has = 
lb
Maria has = 
lb
Difference between the candies Atul and Maria have.
Difference = 
lb
Difference = 
lb
Difference = 
lb
Therefore, Atul have lb of candy more than Maria.
Answer:
B) 5.8
Step-by-step explanation:
the opposite is squared so,
square root of 4 is 2 and 2 squared is 4
Tan(θ) = 3 tan(θ), 0° ≤ θ ≤ 360°
Solve for θ to the nearest degree.
tan(θ) = 3 tan(θ)
Subtract tan(θ) from both sides:
0 = 2 tan(θ)
Divide by 2 both sides:
tan(θ) = 0
If (x,y) is a point on the terminal ray of θ,
then tan(θ) = y/x = 0, and y = 0.
y = 0 ==> θ = 0°, 180°, or 360° in the interval 0° ≤ θ ≤ 360°.
