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Veseljchak [2.6K]
3 years ago
11

Write an equation of the line that passes through the points (1, 2) and (14, 2)

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0

Answer:

y = 2

Step-by-step explanation:


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A bag contains 10 marbles: 4 are green, 4 are red,and 2 are blue. Dale chooses a marble random, and without putting it back, cho
butalik [34]

Answer: for blue its 1/5 or 2/10 while for its 4/9 for green

Step-by-step explanation: since the bag is full you have all 10 marbles. if you put 10 to the 2 that you have it would leave you with 2/10. now simplify that by dividing it by a number that goes into both. in this case both can be divided by 2 so that leaves 2/2 which is 1 and 10/2 which is 5. 1/5 would be the fraction. now you have 9 marbles after you take one and there are 4 green marbles. since there is no number that can divide into both 4 and 9 evenly we just put it as 4/9 having your answer

6 0
3 years ago
And tell me why they are. or not similar​
WARRIOR [948]
Because of the measurements, no but if you notice closely teh shape looks translated or a reflection
8 0
3 years ago
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A baseball camp is held to cmplex that has 6 baseball diamonds.The coaches would like each diamond to have the same number of ca
Ghella [55]

Answer:

  it is NOT possible

Step-by-step explanation:

A number is divisible by 6 if it is even and divisible by 3. It is divisible by 3 if the sum of digits is divisible by 3.

The sum of digits of 152 is 1+5+2 = 8, which is not divisible by 3, so 152 is not divisible by 6.

6 0
3 years ago
If you subtract 12<br> from my number and<br> multiply the difference by -3,<br> the result is -54.
worty [1.4K]

Answer:

the answer is 30

Step-by-step explanation:

Let the number be x

- 3 (x - 12) = - 54

-3x + 36 = -54

-3x = -54 - 36

-3x = -90

x = -90/-3

x = 30

4 0
3 years ago
1-116 1.2.6
ankoles [38]

Answer:

A. 30 adults; B. 24 not dolls

Step-by-step explanation:

A.

\begin{array}{rcl}\text{No. of adults} & = & \text{No. of visitors} \times \text{Fraction who are adults}\\& = & \text{100 visitors} \times \dfrac{\text{3 adults}}{\text{10 visitors}} \\& = & \textbf{30 adults}\\\end{array}

B.

If five-eighths of the prizes were dolls, then three-eighths of the prizes were not dolls.

\begin{array}{rcl}\text{No. not dolls} & = & \text{No. of prizes} \times \text{Fraction not dolls}\\& = & \text{64 prizes} \times \dfrac{\text{3 not dolls}}{\text{8 prizes}} \\& = & \textbf{24 not dolls}\\\end{array}

3 0
3 years ago
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