1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liberstina [14]
3 years ago
10

Translate (1, -2) up 1 unit.

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer:

1,1 brainless pls? ..... ..

lina2011 [118]3 years ago
4 0

Answer:

(-1, -3)

Step-by-step explanation:

Since you are going up one unit, you only change the negative two into a negative three, and you keep the one. Now that you are also reflecting over the x-axis, you change the positive one into a negative one, and you keep the negative three the way it is.

Hope it helps you.

You might be interested in
2. Use the image below to answer problems A-C. Show all work.
Yakvenalex [24]
<span>A. Calculate the value of x.</span>
6 0
3 years ago
You charge customers $18.75 for lube service, parts, and labor. Assuming you take one hour's labor at $15, and the parts cost $3
hram777 [196]
Let
T---------> <span>the tax rate on the parts in $

we know that
$18.75=$15+$3.50+$T
T=18.75-15-3.5
T=$0.25
so
$3.50----------> 100%
$0.25--------> x
x=0.25*100/3.50------> x=7.14%------> x=7.1%

the answer is
7.1%</span>
5 0
2 years ago
To test Upper H 0​: muequals50 versus Upper H 1​: muless than50​, a random sample of size nequals23 is obtained from a populatio
natta225 [31]

Answer:

Step-by-step explanation:

Hello!

1)

<em>To test H0: u= 50 versus H1= u < 50, a random sample size of n = 23 is obtained from a population that is known to be normally distributed. Complete parts A through D. </em>

<em> A) If  ¯ x = 47.9  and s=11.9, compute the test statistic .</em>

For thistest the corresponsing statistis is a one sample t-test

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }~~t_{n-1}

t_{H_0}= \frac{47.9-50}{\frac{11.9}{\sqrt{23} } } = -0.846= -0.85

B) If the researcher decides to test this hypothesis at the a=0.1 level of significance, determine the critical value(s).

This test is one-tailed to the left, meaning that you'll reject the null hypothesis to small values of the statistic. The ejection region is defined by one critical value:

t_{n-1;\alpha }= t_{22;0.1}= -1.321

Check the second attachment. The first row shows α= Level of significance; the First column shows ν= sample size.

The t-table shows the values of the statistic for the right tail. P(tₙ≥α)

But keep in mind that this distribution is centered in zero, meaning that the right and left tails are numerically equal, only the sign changes. Since in this example the rejection region is one-tailed to the left, the critical value is negative.

C) What does the distribution graph appear like?

Attachment.

D) Will the researcher reject the null hypothesis?

As said, the rejection region is one-tailed to the right, so the decision rule is:

If t_{H_0} ≤ -1.321, reject the null hypothesis.

If t_{H_0} > -1.321, do not reject the null hypothesis.

t_{H_0}= -0.85, the decision is to not reject the null hypothesis.

2)

To test H0​: μ=100 versus H1​:≠​100, a simple random sample size of nequals=24 is obtained from a population that is known to be normally distributed. Answer parts​ (a)-(d).

a) If x =104.2 and s=9.6, compute the test statistic.

For this example you have to use a one sample t-test too. The formula of the statistic is the same:

t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } = \frac{104.2-100}{\frac{9.6}{\sqrt{24} } = } = 2.143

b) If the researcher decides to test this hypothesis at the α=0.01 level of​ significance, determine the critical values.

This hypothesis pair leads to a two-tailed rejection region, meaning, you'll reject the null hypothesis at either small or big values of the statistic. Then the rejection region is divided into two and determined by two critical values (the left one will be negative and the right one will be positive but the module of both values will be equal).

t_{n-1;\alpha/2 }= t_{23; 0.005}= -2.807

t_{n-1;1-\alpha /2}= t_{23;0.995}= 2.807

c) Draw a​ t-distribution that depicts the critical​ region(s). Which of the following graphs shows the critical​ region(s) in the​t-distribution?

Attachment.

​(d) Will the researcher reject the null​ hypothesis?

The decision rule for the two-tailed hypotheses pair is:

If t_{H_0} ≤ -2.807 or if t_{H_0} ≥ 2.807, reject the null hypothesis.

If -2.807 < t_{H_0} < 2.807, do not reject the null hypothesis.

t_{H_0}= 2.143 is greater than the right critical value, the decision is to reject the null hypothesis.

Correct option:

B. The researcher will reject the null hypothesis since the test statistic is not between the critical values.

3)

Full text in attachment. The sample size is different by 2 but it should serve as a good example.

H₀: μ = 20

H₁: μ < 20

a) n= 18, X[bar]= 18.3, S= 4, Compute statistic.

t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }= \frac{18.3-20}{\frac{4}{\sqrt{18} } } = -1.80

b) The rejection region in this example is one-tailed to the left, meaning that you'll reject the null hypothesis to small values of t.

Out of the three graphics, the correct one is A.

c)

To resolve this you have to look for the values in the t-table that are the closest to the calculated t_{H_0}

Symbolically:

t_{n-1;\alpha_1 } \leq t_{H_0}\leq t_{n-1;\alpha _2}

t_{H_0}= -1.80

t_{17; 0.025 }= -2.110

t_{17;0.05}= -1.740

Roughly defined you can say that the p-value is the probability of obtaining the value of t_{H_0}, symbolically: P(t₁₇≤-1.80)

Under the distribution the calculated statistic is between the values of -2.110 and -1.740, then the p-value will be between their cumulated probabilities:

A. 0.025 < p-value < 0.05

d. The researcher decides to test the hypothesis using a significance level of α: 0.05

Using the p-value approach the decision rule is the following:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

We already established in item c) that the p-value is less than 0.05, so the decision is to reject the null hypothesis.

Correct option:

B. The researcher will reject the null hypothesis since the p-value is less than α.

I hope this helps!

6 0
3 years ago
Write the fraction as a whole or mixed number.
Wewaii [24]

Answer:

1\frac{1}{2}

Step-by-step explanation:

If there is 1500 cellular phones per 1000 people, then the number of phones per person is:

\frac{1500}{1000} = \frac{15}{10} = \frac{3}{2}

Now we know that \frac{3}{2} = 1 + \frac{1}{2} = 1\frac{1}{2}

5 0
3 years ago
A gourmet candy company charges the
MrRissso [65]
I’m pretty sure it’s C. because half of 12 is 6 so if they’re buying a pound and a half it would be 12+6, which is 18
8 0
2 years ago
Other questions:
  • Find the value of 9-6(8-5)+(-3)
    11·1 answer
  • In science class, Sara needed 8 test tubes for 3 different experiments. The first experiment required 2 test tubes and the other
    5·1 answer
  • Find the coordinates for the midpoint of the segment with endpoints given. (10, 6) and (-4, 8) (7, 7) (3, 7) (7, 3)
    12·2 answers
  • The square root of a number is 2k. what is half of the number?​
    15·1 answer
  • Is it true that the sum of two repeating decimal is always repeating decimal​
    5·1 answer
  • Please help i’ll mark brainlest!!!!!
    6·1 answer
  • In the image, pretty sure 24 is a plane. Not sure about 23.
    13·1 answer
  • In AHIJ, the measure of ZJ=90°, the measure of ZH=57°, and IJ = 22 feet. Find the
    10·1 answer
  • The Leibnitz notation for the chain rule is
    12·1 answer
  • The average 8- to 18-year-old spends____ per day on average in front of a screen doing very little to
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!