Question

Here is a FDT for a small da

Answer 1

Answer:

(a) Mean = 36.05; (b) median = 37; (c) mode = 37  

Step-by-step explanation:

I am assuming your DFT is like this:

$\begin{array}{c|c}\textbf{n} & \textbf{Frequency} \\33 & 0 \\34 & 3 \\35 & 3 \\36 & 3 \\37 & 10 \\\end{array}$

(a) Mean

The mean is the sum of all the data points divided by the number of points. I have done some of the calculations for you in the table below

$\begin{array}{cccc}\textbf{n} & \textbf{f} & \mathbf{n\cdot f} & \mathbf{cf}\\33 & 0 & 0 &0 \\34 & 3&102 &3 \\35 & 3& 105 & 6\\36 & 3 &108 & 9\\37& 10& 370 & 19\\\textbf{SUM} & \mathbf{19}&\mathbf{685} \\\end{array}$

$\begin{array}{rcl}\text{Mean} & = & \dfrac{\sum n}{n}\\\\& = & \dfrac{685}{19}\\\\& = & \mathbf{36.05}\\\end{array}$

(b) Median

The median is the middle value in your list of observations.

Your data set contains 19 terms, so the middle is (19/2)th term.

Count down the column of cumulative frequency (cf) until cf = 9½.

The 9½th term is 37.

Median = 37

(c) Mode

The mode is the value that appears most often in your list of observations.

It is obvious from your table that the number that occurs most frequently is 37.  

Mode = 37

The diagram below shows that the score of 37 is predominant.