To calculate the area of a rectangle you multiply the length of the the sides, on 38) the sides are 4 and (3x-2) so to find the area do 4 x (3x-2) = 12x-8
To find the area of a right angled triangle you multiply the two sides and then divide by two, so for 39) and 40) follow this method but divide by two after as they’re triangles to find the area for these
Answer:
- asymptotes: x = -4, x = 4
- zeros: x = 0
Step-by-step explanation:
The vertical asymptotes of the rational expression are the places where the denominator is zero:
x^2 -16 = 0
(x -4)(x +4) = 0 . . . . . true for x=4, x=-4
x = 4, x = -4 are the equations of the vertical asymptotes
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The zeros of a rational expression are the places where the numerator is zero:
4x = 0
x = 0 . . . . . . divide by 4
Y=mx+c
m1 x m2 = - 1 for perpendicular lines
m= -1/5
so now y= - 1/5x + c
Substitute given coordinate
3= (-1/5 × 3) +c
3= -3/5 + c
add 3/5 to both sides
2.6 (a.k.a 18/5) = y
So therefore:
y=(-x+18)/5
I think this is correct
Answer:
2/4
Step-by-step explanation: