Answer:
y = 2(x-3)^2 - 2
Step-by-step explanation:
y = 2x^2 - 12x + 16
y = 2(x^2 - 6x + 8)
y = 2(x^2 - 6x +8 +1 -1) you "complete the square" by bringing the last term (8) up to "half of the middle co-efficient squared". Middle co-efficient is -6, half is -3, squared is 9. To get from 8 to 9 you must add 1 (+1), but if you add 1 you must subtract 1 (-1) so that you don't change the overall value of inside the bracket
y = 2(x^2 - 6x +9) - 2 (bring the -1 outside of the brackets)
y = 2(x-3)^2 - 2
A set of 3 nonzero whole numbers say (a,b,c) that form the sides of a right triangle and follow the pythagorous theorem

are called a Pythagorean Triple
The example of Pythagorean Triplet are
(3,4,5), (5,12,13) ,(8,15,17), etc.
Hence
A set of 3 nonzero whole numbers that form the sides of a right triangle are called a Pythagorean Triple.
Answer:
B' is at (2.76,-4.9)
Equation of CC' is 11.38x+4.55y= -31.86
or at its slope-intercept form:
y= (-11.38x - 31.86)/4.55
Step-by-step explanation:
From 2x^2 - 162,
factors would include 2(x+9)(x-9), in which x = 9,-9