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steposvetlana [31]
3 years ago
10

A mass weighting 64 pounds, attached to the end of a spring and stretches the spring 0.32 foot. There is no damping and no exter

nal forces acting on the system. The mass is initially released from a point 8 inches above the equilibrium position with a downward velocity of 5 ft/s.
a) Find the displacement at any time t, ut) (find the equation of motion)

b) What are the amplitude and period of motion?

c) How many complete cycles will the mass have completed at the end of 37 seconds?

d) At what time does the mass pass through the equilibrium position heading downward at the second time?

e) At what times does the mass attain its extreme displacements on either side of the equilibrium position?

f) What is the position of the mass at t-3 sec?

g) What is the instantaneous velocity at t-3 sec?

h) What is the acceleration at t=3sec?

i) What is the instantaneous velocity at the time when the mass passes through the equilibrium position?

j) At what time is the mass 5 inches below the equilibrium position?

k) At what time is the mass 5 inches below the equilibrium position heading in the upward direction?
Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

Step-by-step explanation:

Check attachment for solution

Download pdf
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>
25640f23e45fc3ca51eee21fe6956da5.png
3c0bc4790151da6300484a5bbbfebca2.png
65c34024e2fd742e12390af5b2a73368.png
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37 over 100 as a mixed number and a decimal
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The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th
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Answer:

(a)\frac{7}{25}

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Step-by-step explanation:

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Number of seniors who attended prom,n(S)=97

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Number of juniors who did not attend prom,n(J')=56

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(a) P (a junior who did not attend prom)

P(J')=\frac{56}{200}= \frac{7}{25}

(b)

P(Senior)=\frac{116}{200}

P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}

(c)P (junior | attended prom)

P(Senior)=\frac{84}{200}

P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}

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