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lisov135 [29]
3 years ago
7

What is the answer to the following equation?-x • 3x=?

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
The answer is -3 because:
A negative times a postive stays negative and also:
the variable "x" has an invisible one in front of it, so,
-1 x 3 = -3

Hope this helps :)
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For what value of k, the following pair of linear equations has unique solution
riadik2000 [5.3K]

Answer:

uv UC uh uh uh uh uh uh uh all tardy txt tch tch addressed to you and your family a very happy and prosperous new year and I have to go go go go go go go go go go go go in to comes to that and return to me and I will pick ⚒️⛏️ me know if you have u I love you too and miss you too babe I love it ❤️ me know when you're ready tomorrow morning to get the money to you and your team for the impostor

Step-by-step explanation:

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3 years ago
(-11+ √-4) + (4+ √-36)
mash [69]

Answer:

-7 + 8i

Step-by-step explanation:

(-11 + \sqrt{-4}) + (4 + \sqrt{-36}) = (-11 + 2\sqrt{-1}) + (4 + 6\sqrt{-1})

We know \sqrt{-1} is a complex number and is defined by i

∴(-11 + \sqrt{-4}) + (4 + \sqrt{-36}) = (-11 + 2i) + (4 + 6i) = -7 + 8i

4 0
3 years ago
What is the experimental probability of rolling a 3 or 4?
ohaa [14]

If it's 3 or 4 the probability is:

2/6 or 1/3

We call the outcomes in an event its "favorable outcomes". If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is .

7 0
3 years ago
PLEASE ANSWER ASAP!!
Rufina [12.5K]

Answer:

  1. The instantaneous rate of increase of f(x) at x_{0} = 3 is 3.
  2. One possible equation of this line is y = 3x - 16.
  3. The line is tangent to the graph of y = f(x). The slope of the line is the same as the instantaneous rate of increase of f(x) at x_{0} = 3.

Step-by-step explanation:

<h3>1.</h3>

\begin{aligned}&\lim_{h\to 0}{\frac{f(3+h)-f(h)}{h}}\\ =&\lim_{h\to 0}\frac{1}{h} \cdot [(3^{3} + 3 \times 3^{2}h +3\times 3h^{2} + h^{3})- 4(3^{2} + 2\times 3h + h^{2}) + 2 \\[-1em] &\phantom{\lim_{h\to 0}\frac{1}{h}\cdot []} -(3^{3} -4\times 3^{2} + 2)]\\ = &\lim_{h \to 0}\frac{h^{3} + 5h^{2} +3h}{h}\\=& \lim_{h \to 0}{h^{2}} + \lim_{h \to 0}{5h} + \lim_{h\to 0}{3}\\ =& 3\end{aligned}.

<h3>2.</h3>

f(3) = 3^{3} - 4\times 3^{2} + 2 =-7.

In other words, the graph of y = f(x) passes through the point (3, -7) where x = 3.

The point-slope form of a line in a cartesian plane is:

y - y_0 = m (x - x_0).

For this line,

(3, -7) is the point on the line, while

3 is the slope of the line.

The equation of this line will thus be

y - (-7) = 3(x - 3).

That's equivalent to

y = 3x - 16.

<h3>3.</h3>

Refer to the diagram attached. The line touches the graph of y = f(x) at x = 3 without crossing it. The line here is thus a tangent to the graph of y = f(x) at x = 3. The slope of the line represents the instantaneous rate of increase of f(x) at x_{0} = 3.

4 0
3 years ago
All angles in the figure at the right are right angles. What is the area of the figure? The top of the figure is 9 units and the
ladessa [460]

2+2 is 4 minus 1 thats 3 quick maths

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3 years ago
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