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3 years ago

In how many ways can you

Mathematics

2 answers:

marysya [2.9K]3 years ago

7 0

Answer:74613

Step-by-step explanation:

n!/r!(n-r)!

22!/6!(22-6)!

=74613

Sergeu [11.5K]3 years ago

5 0

Answer:

3 r 4

Step-by-step explanation:

22/6= 3.6 recurring so we round down (3.6 → 3)

so 3 remainder 4.

The remainder means left-overs known as 'r'.

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The perimeter of triangle ABC is given by the expression 3x2 - 7x + 2.

VladimirAG [237]

Answer:

Perimeter of ABC = AB + BC+AC. Replace letters with equations.

3x^2-7x+2 = 2x^2-10x+6 + x^2-x-4 + AC = 3x^2-11x+2 + AC.

AC = 4x;

3 0

4 years ago

Read 2 more answers

Suppose you received a score of 95 out of 100 on exam 1 . The mean was 79 and the standard deviation was 8 . If your score on ex

Schach [20]

Answer:

You did the same on both exams.

Step-by-step explanation:

To compare both the scores, we need to compute the z scores of both the exams and then compare the values. The formula for z-score is:

Z = (X - μ)/σ

Where X = score obtained

μ = mean score

σ = standard deviation

For Exam 1:

Z = (95 - 79)/8

= 16/8

Z = 2

For Exam 2:

Z = (90 - 60)/15

= 30/15

Z = 2

The z-scores for both the tests are same hence the third option is correct i.e. you did the same on both exams.

8 0

3 years ago

Is 4/10 more, less or equal to half

zubka84 [21]

Answer:

less

Step-by-step explanation:

5/10 is equal to one half, but 4/10 is less than one half

7 0

3 years ago

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What is the missing value , 2/3 and n/12

gavmur [86]

N=8
If you set 2/3 equal to n/12 then you multiple 3 by 4 to get 12. So you have to multiple 2 by 4 to get N.

8 0

3 years ago

In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank

fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) $Amount \ of \, water \ remaining \ in \, the \ tank \ is \ \frac{x^3(6-\pi) }{6}$

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The volume of the sphere = $\frac{4}{3} \pi r^3$

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = $\frac{4}{3} \pi \frac{x^3}{8}$ = $\frac{1}{6} \pi x^3$

For tank B

Volume of tank = x³

The volume of the spheres = $8 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = $8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}$

For tank C

Volume of tank = x³

The volume of the spheres = $64 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = $64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}$

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The volume of the spheres = $512 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = $512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}$

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = $x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}$

$Amount \ of \ water \, remaining \, in \, the \ tank = \frac{x^3(6-\pi) }{6}$ .

5 0

3 years ago