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alexandr402 [8]
3 years ago
11

1/2 (1.45 + 0.75) + 2 x 8.1

Mathematics
2 answers:
melomori [17]3 years ago
7 0

Answer:

17.3

Step-by-step explanation:

1/2(1.45+0.75)+(2)(8.1)

=1/2(2.2)+(2)(8.1)

=1.1+(2)(8.1)

=1.1+16.2

=17.3

Alexeev081 [22]3 years ago
7 0
17.3 that is the answer hoped this helped a?
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Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe
AlekseyPX
The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}

To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
7 0
3 years ago
Jacob needs less than 5 C's on his transcript to qualify for UGA. He already has 1 C. At most, how many more C's can he get and
victus00 [196]
<span>C' x + 1 < 5 ; x < 4 ...............................................................................................</span>
6 0
3 years ago
Read 2 more answers
Help find the answer for problem number 4
Olin [163]
Adult ticket (a) = $5
Child ticket (c) = $2

785 tickets = $3280

a + c = 785 tickets
5a + 2c = $3280

c = 215 child tickets
a = 570 adult tickets

570 + 215 = 785 tickets
5(570) + 2(215) = $3280

There were 215 child tickets sold on Saturday



3 0
3 years ago
I need help please answer these two questions for me! Will give points.​
jarptica [38.1K]

Answer:

7.) 7

10.)  0

Step-by-step explanation:

When it means "evaluate the function", it's in essence asking us to see what the function spits out when we feed it a certain input. Our inputs are our x values, which spit out a y value.

Evaluating the function when x = 1:

Let's look at where the function has an x value of 1. We see it near the bottom of the table and see the y value associated with the input is 7. So when the function is fed 1 as an input, it spits out 7.

Evaluating the function when f(x) = - 2:

This one is a weird because of the new notation. Just think of it as some value of f, which we don't know (so we represent it as an x-variable) must equal -2. So let's look at our table to find out where our output is -2. We find that when f(x) = -2 the input is 0. So the input which gives -2 is 0.

7 0
2 years ago
I need help ASAP there’s a time limit
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14 uehebeudygwgwvbsbbe
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