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2 years ago

What is the volume of a triangular pyramid that is 4ft tall and has a base area of 3 square feet

1 answer:

4 0

Formula of the Volume of a Pyramid is: $\frac{1}{3}$ ×Area of Base×Height of pyramid
V= $\frac{1}{3}$ ×3×4 (area of base=3 ft²)
V=4 ft³
$\frac{1}{3}$ and 3 cancels out.

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

2 years ago

What is the product for 1/5 times 6/7

Vlad1618 [11]

6/35 is your answer answer answer sorry

5 0

3 years ago

Eastside middle school has 1,500 students. Thirty-two percent of them are in sixth grade. How many sixth-grade students are the

hichkok12 [17]

480 six graders
1,500*0.32 = 480

6 0

2 years ago

What is the value for x?

taurus [48]

Step-by-step explanation:

angle B=6x+4

6x=4

x=4/6

x=0.6

..I got this much...sorry if its wrong

5 0

3 years ago

Read 2 more answers

(3ab+2c)^3 what is the answer

svet-max [94.6K]

Answer:

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

Step-by-step explanation:

$(3ab+2c)^3$

$=(3ab+2c)$ × $(3ab+2c)$ ×

$=(3ab+2c)(9a^2b^2+12abc+4c^2)$

$=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)$

$=27a^3b^3+36a^2b^2c+12abc^2+18a^2b^2c+24abc^2+8c^3$

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

<em>hope this helps....</em>

5 0

2 years ago