Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so
we have
substitute
therefore
The area of triangle K is 16 times greater than the area of triangle J
Well Those are variables and it is using the Distributive property to solve. For example P(a+b) simplify P*a + P*b.
Answer:
x = - 
, x = 
Step-by-step explanation:
to find the points of intersection equate the 2 equations , that is
7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )
6x² - 5x - 25 = 0 ← factor the quadratic on left side
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × - 25 = - 150 and sum = - 5
the factors are - 15 and + 10
use these factors to split the x- term
6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )
3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term
(2x - 5)(3x + 5) = 0
equate each factor to zero and solve for x
3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = -
2x - 5 = 0 ⇒ 2x = 5 ⇒ x =
Answer:
C. x^14
Step-by-step explanation:
(x^9)^0 is 1
(x^7)^2 is x^14
x^14*1 is x^14
The Answer is C. x^14
Hope this helps!
Answer:
The answer is in the web link
Step-by-step explanation:
1.) https://shsmrward.weebly.com/uploads/1/0/0/3/10037735/independentdependent_ak.pdf
