Answer:
Step-by-step explanation: It’s the perimeter of each shape so you add the outside of the shape up. The second question is 11.2 and 12 as the width and length. The 11.2 is the width so on the other side it is 11.2, and the length is 12 so the other side is 12. You then add them all up and get your answer.
Answer:
option B
3
Step-by-step explanation:
Given in the question an expression
Whole numbers are positive numbers, including zero, without any decimal or fractional parts.
Possible range of domain will be 1 ≤ x ≤ 48
We know that perfect square between 1 and 48 are
1 , 4 , 16 , 25 , 36
1)
x = 3
√48/3 = √16 = 4
2)
x = 12
√48/12 = √4 = 2
3)
x = 48
√48/48 = √1 = 1
5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
<span>22 + (3^2 – 4^2)
= </span><span>22 + (9 – 16)
</span><span>= 22 -7
= 15</span>
Answer:
x int: (4,0)
Step-by-step explanation:
make y=0
x^2-4x=0 add 4 to both sides
x^2=4x divide by x
x=4
