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3 years ago

What is the percent amount and base of 20% of 50

Mathematics

2 answers:

nadya68 [22]3 years ago

6 0

20% x 50=0.2 x 50=10
☺☺☺☺

marta [7]3 years ago

5 0

20 % × 50 =
= 20 × 50 ÷ 100
= 1000 ÷ 100
= 10

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TiliK225 [7]

Answer:

The relation passes the vertical line test.

Step-by-step explanation:

When you graph the points, a vertical line can be drawn through them without hitting another point.

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3 years ago

ed fills his sports bottle with 1.2 liters of water after his bike ride he drinks 200 millimeters of water how much water is lef

Iteru [2.4K]

1,2 liters of water = 1.200 millimeters so if he drinks 200 millimeters he has 1,000 millimeters left or 1 liter of water left

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3 years ago

Show the processes for solving 2x+3y=5 and 4x - y=17 using elimination and substitution

r-ruslan [8.4K]

ANSWER:

The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).

SOLUTION:

Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).

Let us first solve the above equations using elimination process. 

For elimination, one of the coefficients of variables has to be same in order to cancel them.

Now solve (1) and (2)

eqn (1) $\times$ 2 → 4x + 6y = 10

eqn (2) → 4x – y = 17

(-) ----------------------------

0x + 7y = -7

y = -1

Substitute y value in (2)

$4 x-(-1)=17 \rightarrow 4 x+1=17 \rightarrow 4 x=17-1 \rightarrow 4 x=16 \rightarrow x=4$

So, solution of two equations is (4, -1).

Now let us solve using substitution process.

Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17

Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56

x = 4

Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1

Hence, the solution of the two equations is (4, -1).

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3 years ago

Simplify the given equation in the attached picture: \sqrt{29-\sqrt{5}}

Vilka [71]

Answer: 2√5 - 3

Step-by-step explanation:

$Simplify the following:$\sqrt{29-12 \sqrt{5}}$$$\begin{aligned}&29-12 \sqrt{5}=9-12 \sqrt{5}+20=9-12 \sqrt{5}+4(\sqrt{5})^{2}=(2 \sqrt{5}-3)^{2}: \\&\sqrt{\left((2 \sqrt{5}-3)^{2}\right)}\end{aligned}$$Cancel exponents. $\sqrt{(2 \sqrt{5}-3)^{2}}=2 \sqrt{5}-3$ :\\Answer:$$2 \sqrt{5}-3$