You can solve the median by putting all the numbers in order. Then cross off one at a time at the start, then cross off the one at the end, then keep going until you get to one.
You can solve the mode by looking for the most frequent number. I remembered that by looking at mode and seeing MO and remembering most often.
I hope this helps :-)
If you plug in the x-coordinate into your equation for the line, you get
y = -3(4)/4 + 3
y = -3 + 3
y = 0
Answer:
46
Step-by-step explanation:
∠DAC ≅ ∠ACB because they are opposite interior angles where transversal AC crosses parallel lines BC and AD.
∠DAC ≅ ∠CAB because they are corresponding angles of the similar triangles ΔABC and ΔACD.
Hence ∠ACB ≅ ∠CAB and ΔABC is isosceles with side lengths both being 9. The corresponding side lengths of ΔACD are 12, meaning the base of ΔABC, segment AC, is 12. The scale factor of ΔACD to ΔABC is then 12:9 = 4:3, so the base AD of ΔACD is (4/3)×12 = 16.
So, the side lengths of the trapezoid are ...
- AB = 9
- BC = 9
- CD = 12
- DA = 16
and the perimeter is 9 +9 +12 +16 = 46 units.
Answer:
<h3>NO SOLUTIONS</h3>
Step-by-step explanation:
To solve this problem, first, you have to isolate x on one side of the equation.
3x/2-2>7
3x/2-2-7>7-7 (First, subtract 7 from both sides.)
7-7 (Solve.)
7-7=0
3x/2-2-7>0
3x/2-2*0-7*0>0*0 (Then, multiply 0 from both sides.)
0*0 (Solve & simplify.)
0*0=0 (undefined & no solutions)
In conclusion, there are no solutions.
x=13 because you put all of them in an equation and set them equal to 180 bc that is how many degrees are in a triangle so it would be 6x+19+5x-15+3x-6=180 and then you solve the equation so it would be 14x-2=180 then you would add to to both side which would cancel out on the left and make 182 on the right then divide 182 by 14 and you get 13.
