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denpristay [2]
3 years ago
13

Carl has three lengths of cables, 5/6 yard long, and 2/3 yard long. If he uses 1 yard of cable, how much cable is left?

Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer: 1/6th

Step-by-step explanation:idk fr

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Angle 1 and Angle 2 are supplementary. Angle 1 is 20 degree less than nine times the size of angle 2.
nadya68 [22]

Answer:

∠1=160° and ∠2=20°

Step-by-step explanation:

Let ∠1 = x

∠2 = y

as these two angles are supplementary their sum is 180

that x+y=180   ----(A)

Also given that ∠1 is 20 degree less than nine times the size of ∠2.

Hence

x=9y-20

putting value of x in A and solving for y

9y-20+y=180

10y=180+20

10y=200

y=10

Putting this y in A

x+10=180

x=160

5 0
3 years ago
270 is ninety percent of what number ?
harina [27]
The correct answer is 300.
6 0
3 years ago
The probability distribution for a random variable x is given in the table. -5 -3 -2 0 2 3 Probability .17 .13 33 16 11 10 Find
IgorLugansk [536]

Answer:

0.79

Step-by-step explanation:

add up the probability that is less than or equal to  0, which is 0.17+0.13+0.33+0.16 = 0.79

5 0
2 years ago
Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).
PilotLPTM [1.2K]
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,


y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
5 0
2 years ago
A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w
Rasek [7]

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

6\mleft(6.5x+2.5\mright)

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

6(6.5x+2.5)+A=6.5(8x+6)

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}

The answer is:

13x+24

7 0
9 months ago
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