Answer: y=3x-6
Step-by-step explanation:
Answer:
The rule of the arithmetic sequence is 13 - 2n
The 30th term is -47
Step-by-step explanation:
∵ f(n) = 11 and g(n) = -2(n - 1) = -2n + 2
∴ f(n) + g(n) = 11 + -2n + 2 = 13 - 2n
Use n = 1 , 2 , 3 , 4 to check the type of the sequence
∵ n = 1 ⇒ 13 - 2(1) = 11
∵ n = 2 ⇒ 13 - 2(2) = 13 - 4 = 9
∵ n = 3 ⇒ 13 - 2(3) = 13 - 6 = 7
∵ n = 4 ⇒ 13 - 2(4) = 13 - 8 = 5
∵ 11 , 9 , 7 , 5 is an arithmetic sequence with difference -2
∴ The rule of the arithmetic sequence is 13 - 2n
∴ The 30th term = 13 - 2(30) = -47
So assuming that 25cm is 25 square cm because you cannot have a 2 dimentional cake so
600mm by 500mm
to find the area, multiply legnth by width
mm=milimeters
cm=centimeters
this is in mm so
1cm=10mm
1mm=1/10cm
to convert from mm to cm, you divide by 10
we must divide by 10 first
legnth =600mm
600/10=60cm
legnth=60cm
width=500mm
500/10=50cm
width=50cm
area=60 times 50=3000 square cm or cm^2
so 3000 is the area
25 is the area of each cake
divide 3000 into 25 and find how many cakes will fit
3000/25=120
120 cakes will fit
Below is the solution:
A(final)=16cm^2 ds/dT=6 da/dT=?
<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>
<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm)
</span>
<span>Answer should be da/dT=48cm^2/sec
</span>
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Answer:
y=-\frac{5}{3} x+\frac{10}{3} or what is the same: 
Step-by-step explanation:
First we find the slope of the line that goes through the points (-4,10) and (-1,5) using the slope formula: 
Now we use this slope in the general form of the slope- y_intercept of a line:

We can determine the parameter "b" by requesting the condition that the line has to go through the given points, and we can use one of them to solve for "b" (for example requesting that the point (-1,5) is on the line:

Therefore, the equation of the line in slope y_intercept form is:

Notice that this equation can also be written in an equivalent form by multiplying both sides of the equal sign by "3", which allows us to write it without denominators:
