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Elodia [21]
2 years ago
5

Which graph represents the function p(x) = |x – 1|?

Mathematics
2 answers:
kotegsom [21]2 years ago
5 0

Answer:

the second one of course

Rasek [7]2 years ago
5 0

Answer:

B

Step-by-step explanation:

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In the diagram below, ΔPQR ≅ ΔSTR. Complete the statement ∠PRQ ≅ ___ A. ∠SRT B. ∠RST C. ∠STR D. ∠T
Oduvanchick [21]

The complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

<h3>Similar triangles </h3>

From the question, we are to complete the given statement

From the given information,

We have that ΔPQR ≅ ΔSTR

This means ΔPQR is congruent to ΔSTR

Then,

∠PQR ≅ ∠STR

∠PRQ ≅ ∠SRT

∠QPR ≅ ∠TSR  

Hence, the complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

Learn more on Congruent Triangles here: brainly.com/question/28032367

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4 0
1 year ago
Please help me out with equations in math!<br> Its a starr review!
Alexeev081 [22]

Answer:

F

Step-by-step explanation:

Multiply -3 by 6.5 and you'll get your answer :)

I hope I helped!

4 0
2 years ago
Which is a perfect square?<br> 0 5<br> 0 8<br> 36<br> 44
Liono4ka [1.6K]

Answer:

C) 36

Step-by-step explanation:

Because 6^2=6*6=36.

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS! ASAP!!!!!!!
marusya05 [52]

Hold on i believe its C but let me go look on google and i'll get back to you to sure

3 0
3 years ago
Refer to the rectangle below. The length of the rectangle is x + 12. The width of the rectangle is x + 3.
Elis [28]

Answer:

x^2+15x+36

Step-by-step explanation:

The complete question is shown in the attachment.

The length of the rectangle is x + 12. The width of the rectangle is x + 3.

Recall that area of a rectangle is Length \times Width

In terms of x, the area is (x+12)(x+3)

Recall the distributive property of real numbers: (a+b)(c+d)=a(c+d)+b(c+d)

We apply this property to get:

(x+12)(x+3)=x(x+3)+12(x+3)

We expand again to get:

(x+12)(x+3)=x^2+3x+12x+36

We now simplify to obtain:

(x+12)(x+3)=x^2+15x+36

The area of the rectangle is x^2+15x+36

4 0
2 years ago
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