If Sa=2πrh+2π
v=π
then the surface area is π
and volume is
(rh-2h)/2r.
Given Sa=2πrh+2π
=π.
We have to find surface area and volume from the given expression.
Volume is basically amount of substance a container can hold in its capacity.
First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.
2πrh+2πv=πh
Keeping the term containing v at left side and take all other to right side.
2πv=π-2πrh
v=(πh-2πrh)/2π
v=π/2π-2πrh/2π
v=h/2-h/r
v=h(r-2)/2r
Put the value of v in Sa=2πrh+2π
Sa=2πrh+2π*h(r-2)/2r
=2πrh+2πrh(r-2)/2
=2πrh+πrh(r-2)
=2πrh+πh-2πrh
=πh
Hence surface area is πh and volume is h(r-2)/2.
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Answer: Option D.
Step-by-step explanation:
To solve this exercise you must keep on mind the Angle at the Center Theorem.
According to the Angle at the Center Theorem, an inscribed angle is half of the central angle.
Therefore, given in the inscribed angle m∠BAC=35°, you can calculate the central angle m∠EFD as following:
- Solve for EFD.
- When you substitute values. you obtain:
There’s 15 all together because 10+5=15
They each go up by 5 :) 2+5=8 8+5=14 etc.
Answer:
The answer is m=12
Step-by-step explanation:
1.) combine like terms on both sides of the equation.
2.) After all like terms are combined, divide 250 from both sides.
3.) m=12
